Answer with Step-by-step explanation:
We are given that

We have to find T,N and B at the given point t > (1,
,1)



Now, substitute t=1













___________________
Please, give me some minutes to take over your question
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Rate = miles / time
8/t = 7/ 35
Dividing by 7
8/t = 7/ 35
8/ 7t = 1/ 35
Multiplying by t
8/7 = t/35
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Options
1) 8/t = 35/ 7 (False, t/8 = 35/ 7 )
2) t/8 = 7/ 35 (False, t/8 = 35/ 7 )
3) 8/7 = t/ 35 (TRUE)
4) 7/8 = t/35 (False, 8/7 = t/ 35 )
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Answer
3) 8/7 = t/ 35 (TRUE)
Answer:
A
Step-by-step explanation:
well some people like to go on a budget and others prefer not to because they rather spend their money money on wants rather than needs so I really hope this helps.
use the distributive property
combine alike terms
add the negative number to the other side
combine alike terms
then divide on both sides to get the variable by itself
The probability that both of the students are on Team D is about 5.56%
There are 4 teams, so the first person has a 1/4 chance of being on Team D.
However, for the second person, there are only 6 spots left out of 27 to be on Team D.
To find the combined probability, we need to multiply the two fractions.
1/4 times 6/27 = 1/18 or about 5.56%