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mash [69]
3 years ago
6

Which equation correctly applies the distributive property?

Mathematics
2 answers:
mariarad [96]3 years ago
8 0
That would be -1.5·(6·1.25)=(-1.5·6)·1.25
Arturiano [62]3 years ago
7 0
The first one.............
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Solve the system by substitution.<br> 4y =<br> 5x -10y =-50
Trava [24]

Answer:

x = -20 ; y =-5

Step-by-step explanation:

Eqn. 1 ----> 4y = x

Eqn. 2 ----> 5x-10y = -50

(Simplifying eqn.2 further)

=>5(x-2y)=-50

=>x-2y=\frac{-50}{5} =-10

(Substituting the value of x from eqn. 1)

=>4y-2y=-10

=>2y=-10

=>y =\frac{-10}{2} =-5

Now, substituting the value of y in eqn. 1 ,

x = 4*(-5)=-20

7 0
2 years ago
G verify that the divergence theorem is true for the vector field f on the region
Alenkasestr [34]
\mathbf f(x,y,z)=\langle z,y,x\rangle\implies\nabla\cdot\mathbf f=\dfrac{\partial z}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial x}{\partial z}=0+1+0=1

Converting to spherical coordinates, we have

\displaystyle\iiint_E\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=6}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=288\pi

On the other hand, we can parameterize the boundary of E by

\mathbf s(u,v)=\langle6\cos u\sin v,6\sin u\sin v,6\cos v\rangle

with 0\le u\le2\pi and 0\le v\le\pi. Now, consider the surface element

\mathrm d\mathbf S=\mathbf n\,\mathrm dS=\dfrac{\mathbf s_v\times\mathbf s_u}{\|\mathbf s_v\times\mathbf s_u\|}\|\mathbf s_v\times\mathbf s_u\|\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=\mathbf s_v\times\mathbf s_u\,\mathrm du\,\mathrm dv
\mathrm d\mathbf S=36\langle\cos u\sin^2v,\sin u\sin^2v,\sin v\cos v\rangle\,\mathrm du\,\mathrm dv

So we have the surface integral - which the divergence theorem says the above triple integral is equal to -

\displaystyle\iint_{\partial E}\mathbf f\cdot\mathrm d\mathbf S=36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(\mathbf s_v\times\mathbf s_u)\,\mathrm du\,\mathrm dv
=\displaystyle36\int_{v=0}^{v=\pi}\int_{u=0}^{u=2\pi}(12\cos u\cos v\sin^2v+6\sin^2u\sin^3v)\,\mathrm du\,\mathrm dv=288\pi

as required.
3 0
3 years ago
Find the missing side.<br> 6 is A^2 <br>10 is B^2<br> what is the missing side​
topjm [15]

Answer:

8

Step-by-step explanation:

This is a right triangle, which fits the Pythagorean Theorem, a^2 +b^2 = c^2. The variables a, b, and c all are sides of the triangle, while a and b are the two legs and c is the hypothenuse.

In this problem, we see that 6 and x are the legs and 10 is the hypothenuse.    We put 6 as "a" and x as "b" (but it doesn't matter which is a and b) and 10 is c. Therefore, we have the equation:

6^2 + x^2 = 10^2

which further simplifies to:

36 + x^2 = 100

x^2 = 64

and so x would equal 8 (or -8, but it is impossible to have a side length of -8).

Therefore, the missing side is 8.  

7 0
3 years ago
Read 2 more answers
PLEASE HELP explain how you can prove two circles are similiar
marissa [1.9K]

Answer:

By Looking at the shapes and sizes

Step-by-step explanation:

If you can try and look at the shape and size of it, if you can draw it, draw it on a piece of paper, trace them both, but in the same spot, you didn't specificize, if it was a sphere or just a regular circle or not, so thats all i can tell you.

8 0
3 years ago
Deka measured the mass of 100 sheets of paper as 1,500 grams. How many kilometers would 1 sheet of paper weigh?
Ray Of Light [21]
100=1500g so 10=150g so 1=15g
3 0
3 years ago
Read 2 more answers
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