All categories

3 years ago

Which equation correctly applies the distributive property?

Mathematics

2 answers:

mariarad [96]3 years ago

8 0

That would be -1.5·(6·1.25)=(-1.5·6)·1.25

Arturiano [62]3 years ago

7 0

The first one.............

You might be interested in

If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago

A rancher with 750 ft of fencing wants to enclose a rectangular area and then divide it into four pens with fencing parallel to

Pavel [41]

2 W + 5 L = 750 ft
5 L = 750 - 2 W
L = 150 - 2 W / 5
A ( W ) = W * ( 150 - 2 W / 5 )
A function that models the total area:
A ( W ) = 150 W - 2 W² / 5
A` ( W ) = 150 - 4 W / 5
150 - 4 W / 5 = 0
4 W / 5 = 150
W = 187.5 ft
The largest possible area:
A = 150 * 187.5 - (2 * 187.5² ) / 5 = 28,125 - 14,062.5 = 14,062.5 ft²

7 0

3 years ago

The midsegment through the legs of an isosceles triangle is 4 in. Find the sides of the triangle if its perimeter is 20 in. 75 p

Pani-rosa [81]

The midsegment is half the length of the base. So the base = 2*4 = 8 in.

Since it is an isosceles triangle, the other two sides are equal in length.

Perimeter = sum of two equal sides + base = 20 in.

2x equal side + 8 = 20

equal side = 12/2 = 6

Each of the equal sides = 6"

4 0

3 years ago

Read 2 more answers

Please help practice Questions!<br> will give thanks and star ratings<br> (Question is attached)

zzz [600]

Second one second column

3 0

3 years ago

Read 2 more answers

Simplify : (√ + √ ) (√ − √) ( + )( 2 + 2 )

jek_recluse [69]

$(\sqrt{x}+\sqrt{y})(\sqrt{x}-\sqrt{y})(x+y)(x^2+y^2)\\\\=[(\sqrt{x})^2-(\sqrt{y})^2](x+y)(x^2+y^2)\\\\=(x-y)(x+y)(x^2+y^2)\\\\=(x^2-y^2)(x^2+y^2)\\\\=(x^2)^2-(y^2)^2\\\\=x^4-y^4$

$Used:\\\\(\sqrt{a})^2=a\\\\(a-b)(a+b)=a^2-b^2\\\\(a^n)^m=a^{nm}$

6 0

3 years ago