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3 years ago

Benny’s age is currently 200% of his sister Jenny’s age. What percent of Benny’s age will Jenny’s age

Mathematics

1 answer:

Sav [38]3 years ago

7 0

Answer:

The lower the age of Benny and Jenny, the% between the age of both, the more it decreases

Step-by-step explanation:

To calculate the exact percentage, the age of one of the two is necessary. I demonstrate it with several examples.

Let B be Benny's age

Let J be Jenny's age

We are told that Benny's age is 200% Jenny's age, we know that 200% is 2, therefore:

B / J = 2

Now if B = 2 and J = 1

2/1 = 2

After 4 years:

B + 4 / J + 4 = (2 + 4) / (1 + 4) = 1.2, i.e. 120%

Another example, if B = 4 and J = 2

4/2 = 2

After 4 years:

B + 4 / J + 4 = (4 + 4) / (2 + 4) = 1.33, that is 133%

Another example, if B = 6 and J = 3

6/3 = 2

After 4 years:

B + 4 / J + 4 = (6 + 4) / (3 + 4) = 1.43, that is 143%

The conclusion is that the lower the age of Benny and Jenny, the% between the age of both, the more it decreases.

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Sarah would like to make a 6 lb nut mixture that is 60% peanuts and 40% almonds. She has several pounds of a mixture that is 80%

ivolga24 [154]

Answer:

a. The system of equations that models the situation is....

$0.80x+0.50y=3.60\\\\ 0.20x+0.50y=2.40$

b. The solution to the system: x = 2 and y = 4

The amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

Step-by-step explanation:

Suppose, the amount of 80/20 mixture is $x$ pounds and the amount of 50/50 mixture is $y$ pounds.

So, the amount of peanuts in 80/20 mixture $= 0.80x$ pound and the amount of almonds in 80/20 mixture $=0.20x$ pound.

And the amount of peanuts in 50/50 mixture $=0.50y$ pound and the amount of almonds in 50/50 mixture $=0.50y$ pound.

Now, Sarah would like to make a 6 pounds nut mixture that is 60% peanuts and 40% almonds.

So, the amount of peanuts in that mixture $=(6\times 0.60)=3.60$ pounds

and the amount of almonds in that mixture $=(6 \times 0.40)= 2.40$ pounds.

So, the system of equations will be.........

$0.80x+0.50y=3.60 ...................(1)\\\\ 0.20x+0.50y=2.40...................(2)$

Subtracting equation (2) from equation (1), we will get.....

$(0.80x+0.50y)-(0.20x+0.50y)=3.60-2.40\\ \\ 0.60x=1.20\\ \\ x= \frac{1.20}{0.60}=2$

Now, plugging this $x=2$ into equation (1), we will get......

$0.80(2)+0.50y=3.60\\ \\ 1.60+0.50y=3.60\\ \\ 0.50y=3.60-1.60=2\\ \\ y=\frac{2}{0.50}=4$

So, the amount of 80/20 mixture is 2 pounds and the amount of 50/50 mixture is 4 pounds.

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3 years ago

25.5 divided by 1.25

Artist 52 [7]

the answer is 20.4 and I hope this helps!

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3 years ago

Sanjay had a case of 24 bottles of water. In the first week Sanjay drank 3/8 of the bottles of water. In the second week Sanjay

Gnom [1K]

Answer:

The answer to your question is: 5 bottles

Step-by-step explanation:

Process

First week

Divide 24 by 8

24/8 = 3 bottles = 1/8

but Sanjay drank 3/8 = 9 bottles

And there are 24 - 9 bottles left = 15

- Second week

Divide 15 by 3

15/3 = 5 then 5 bottles = 1/3

but sanjay drank 2/3 = 10 bottles

Then, there are 15 - 10 bottles left = 5

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3 years ago

4. If DF = 9x - 39, find EF. Help I’m so confused!!!!

topjm [15]

Answer:

EF =58

Step-by-step explanation:

from the illustration,

EF =DF - DE

given that DF =9x-39 , DE =47 EF=3x +10

substitute them into the formula,

3x +10=9x-39 - 47

solving for x

3x +10 =9x -86

grouping like terms

3x - 9x =-86 -10

-6x=-96

dividing through by -6

 $\frac{ - 6x}{ - 6} = \frac{ - 96}{ - 6}$ 

 $x = \frac{96}{6}$ 

 $x = 16$ 

but EF=3x+10

substitute x=16 into it to get the EF

EF= 3(16)+10

EF=48+10

EF=58

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3 years ago

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IRISSAK [1]

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