Let F(X) = x^2-16x+71. What is the vertex and minimum value of F(X)?
1 answer:
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Step-by-step explanation:
<u>Step 1: Substitute x from the second equation into the second one</u>
<u>Step 2: Substitute y into the second equation</u>
Answer:
What can a denominator never be?
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.
so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2
0
so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.
so, what x values make our denominator 0?
to figure this out, we need to set (x-1)(x-2)=0
now we split and solve.
so when x is 1 or 2 the function doesnt make sense.
but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2