Answer:
-5 × -5 × -5
Step-by-step explanation:
-5^3 = -5 × -5 × -5
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
m∠JKL = 120°
Step-by-step explanation:
The measure of an angle formed by a two tangents drawn from a point outside the circle is the the difference of the intercepted arcs
minor arc JL = 60 major arc JL = 360 - 60 = 300
m∠JKL = 1/2(300 - 60) = 1/2(240) = 120
Answer: (B)
Step-by-step explanation: 614 square cm.
