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4 years ago

7

Let F(X) = x^2-16x+71. What is the vertex and minimum value of F(X)?

1 answer:

LekaFEV [45]4 years ago

7 0

The veretx is normally the minimum value
hack:
for f(x)=ax²+bx+c
the x value of the vertex is -b/2a
so
f(x)=1x²-16x+71
x value is -(-16)/(2*1)=16/2=8
find f(8) to find y value of vertex

f(8)=8²-16(8)+71
f(8)=64-128+71
f(8)=7

the vertex is (8,7)
the minimum value is 7

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<em><u>Solution:</u></em>

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