Anything that with a denominator that is a multiple of 4, for example:
![\frac{2}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B8%7D%20)
,
![\frac{3}{12}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B12%7D%20)
,
![\frac{4}{16}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B16%7D%20)
,
![\frac{5}{20}](https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B20%7D%20)
, and so on.
Hope this helps you =)
I am pretty sure the answer is 470.4
The ratio adults to students is 1:6
Multiply both sides by 60 so that the right side is 360 and it is
60:360
Therefore there needs to be 60 adults which is option D
Hope this helps :)
Answer:
X = 4, AM = 13u
Step-by-step explanation:
2X + 5 = 3X + 1 (because M is the midpoint)
Then: 5 - 1 = 3X - 2X
SO: X = 4
Answer:
![(2a-b)(a-2b) = 0](https://tex.z-dn.net/?f=%282a-b%29%28a-2b%29%20%3D%200)
Step-by-step explanation:
We can use the quadratic formula to factor this expression
For a quadratic function of the form:
![na ^ 2 + ma + c](https://tex.z-dn.net/?f=na%20%5E%202%20%2B%20ma%20%2B%20c)
Whe have:
![2a^2 + 2b^2 - 5ab](https://tex.z-dn.net/?f=2a%5E2%20%2B%202b%5E2%20-%205ab)
Then:
![n = 2\\\\m = -5b\\\\c = 2b^2](https://tex.z-dn.net/?f=n%20%3D%202%5C%5C%5C%5Cm%20%3D%20-5b%5C%5C%5C%5Cc%20%3D%202b%5E2)
The quadratic formula is:
![a =\frac{-m\±\sqrt{m^2-4nc}}{2n}](https://tex.z-dn.net/?f=a%20%3D%5Cfrac%7B-m%5C%C2%B1%5Csqrt%7Bm%5E2-4nc%7D%7D%7B2n%7D)
Then the solutions are:
![a= \frac{-(-5b)\±\sqrt{(-5b)^2 -4(2)(2b^2)}}{2(2)}\\\\a = \frac{5b\±\sqrt{25b^2-16b^2}}{4}\\\\a = \frac{5b\±3b}{4}\\\\a_1=2b\\\\a_2 =\frac{b}{2}](https://tex.z-dn.net/?f=a%3D%20%5Cfrac%7B-%28-5b%29%5C%C2%B1%5Csqrt%7B%28-5b%29%5E2%20-4%282%29%282b%5E2%29%7D%7D%7B2%282%29%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B5b%5C%C2%B1%5Csqrt%7B25b%5E2-16b%5E2%7D%7D%7B4%7D%5C%5C%5C%5Ca%20%3D%20%5Cfrac%7B5b%5C%C2%B13b%7D%7B4%7D%5C%5C%5C%5Ca_1%3D2b%5C%5C%5C%5Ca_2%20%3D%5Cfrac%7Bb%7D%7B2%7D)
Finally The factored expression is:
![a-\frac{b}{2} = 0\\\\2a -b = 0\\\\](https://tex.z-dn.net/?f=a-%5Cfrac%7Bb%7D%7B2%7D%20%3D%200%5C%5C%5C%5C2a%20-b%20%3D%200%5C%5C%5C%5C)
and
![a-2b= 0](https://tex.z-dn.net/?f=a-2b%3D%200)
Then
![2a^2 + 2b^2 - 5ab = (2a-b)(a-2b) = 0](https://tex.z-dn.net/?f=2a%5E2%20%2B%202b%5E2%20-%205ab%20%3D%20%282a-b%29%28a-2b%29%20%3D%200)