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Lady_Fox [76]
2 years ago
11

a bag has a total of 120 notes in denominations of rs 2, rs. 5 and rs. 10. the total value of the notes in the bag is rs 760. if

there were twice as many notes rs. 5 , the total value of the notes will be 960. find the number of rs 10 notes in the bag?
Mathematics
1 answer:
Deffense [45]2 years ago
8 0
So there are three variables, rs2 label x, rs5 label y, rs10 label z
Lets write equeations using these variables. 
x+y+z=120  (<span>A bag has a total of 120 notes)
2x+5y+10z=760  (total value)
2x+5*2y+10z=960  (twice as many rs5)

3 variables, 3 independent equations will give solution. There are a fair few ways to solve this. </span>
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2 years ago
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What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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12b)
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