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love history [14]
3 years ago
15

Can someone help me here ASAP? this question is worth 20 points. will mark the brainliest, thank you so much in advanced.

Mathematics
1 answer:
worty [1.4K]3 years ago
3 0

Answer:

1. a) (1-1) (1-2) (1-3) (2-1) (2-2) (3-1)

2. a) (5-1) (5-2) (5-3) (5-4) (5-5) (5-6)

3. d) (1-3) (2-3) (3-1) (3-2) (3-4) (3-5) (3-6) (4-3) (5-3) (6-3)

Step-by-step explanation:

1. added the numbers in the parenthesis and A had all of the sums less than 5

2. A had all the 5s in the first spot

3. D had the  3s in each parenthesis

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A bottle contains 3.5 L of water. A second bottle contains 3750 mL of water. How many more millimeters are in the larger bottle
weeeeeb [17]
Hey there,
3.5 L = 3.5 x 1000
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The second bottle has more water than the first bottle,
3,750 mL - 3,500 mL = 250 mL

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4 0
4 years ago
Read 2 more answers
Consider the right triangle below.
EastWind [94]

Answer:

0---------------

Step-by-step explanation:

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Art [367]

Answer:

\displaystyle E=26log2-24log3+8log 5

Step-by-step explanation:

<u>Logarithms</u>

There are certain properties of the logarithms we'll need to recall in order to simplify the expression given in the question. We'll list them below

log(x.y)=logx+logy\\log(x/y)=logx-logy\\logx^y=y.logx

We'll also need to factor the following numbers into their prime factors:

20=2^2\cdot 5

16=2^4

15=3\cdot 5

25=5^2

24=2^3\cdot 3

81=3^4

80=2^4\cdot 5

The original expression is

\displaystyle E=log20+16log\frac{16}{15}+12log\frac{25}{24}+log\frac{81}{80}

Plugging in the factored values

\displaystyle E=log(2^2\cdot 5)+16log\frac{2^4}{3\cdot 5}+12log\frac{5^2}{2^3\cdot 3}+log\frac{3^4}{2^4\cdot 5}

Applying the properties we have

\displaystyle E=log2^2+log 5+16(log2^4-log3-log 5)+12(log5^2-log2^3-log 3)+log3^4-log2^4-log 5

\displaystyle E=2log2+log 5+16log2^4-16log3-16log 5+12log5^2-12log2^3-12log 3+log3^4-log2^4-log 5

\displaystyle E=2log2+log 5+64log2-16log3-16log 5+24log5-36log2-12log 3+4log3-4log2-log 5

Simplifying

\boxed{\displaystyle E=26log2-24log3+8log 5}

7 0
4 years ago
What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall
scZoUnD [109]

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

7 0
4 years ago
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