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rusak2 [61]
3 years ago
15

A machine shop produces metal frames on two different machines. The average daily production on machine 1 is 300 frames, and the

average daily production on machine 2 is 180 frames. What is the daily machine productivity?
Mathematics
1 answer:
statuscvo [17]3 years ago
4 0

Answer:

The daily shop productivity is 480 frames

Step-by-step explanation:

The daily machine productivity refers to the TOTAL production made in a day.

The problem says that a shop produces metal on two different machines. It means that you must take into account the daily production of each one for finding the total production.

The first machine produces 300 frames in a day.

The second machine produces 180 frames in a day too.

So, if the first and the second machines are working together in a single day, the TOTAL daily production is the sum of the production of each one.

production=300+180=480

Thus, the daily shop productivity is 480 frames

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Use the method of cylindrical shells to find the volume v generated by rotating the region bounded by the curves about the given
kondor19780726 [428]

Answer:

The volume is \frac{16\pi}{e}

Step-by-step explanation:

* Lets talk about the shell method

- The shell method is to finding the volume by decomposing

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- Consider a region in the plane that is divided into thin vertical  

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- If each vertical rectangle is revolved about the y-axis, we

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- The resulting volume of the cylindrical shell is the surface area 

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* Lets solve the problem

- To find the volume V generated by rotating the region bounded

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- Consider that the height of the cylinder is y = (4e^x - 4e^-x)

- Consider that the radius of the cylinder is x

- The limits are x = 0 and x = 1

- Lets take 2π and 4 as a common factor out the integration

∴ V=\int\limits^1_0 {2\pi x(4e^{x}-4e^{-x})} \, dx

∴ V=2\pi(4)\int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx

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∵ u = x

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∵ v' = dv/dx = e^x

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∴ v=\int\ {e^{x}}\, dx= e^{x}

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∵ u = x

∴ u' = du/dx = 1

∵ v' = dv/dx = e^-x

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∴ v=\int\ {e^{-x}} \, dx=-e^{-x}

∴ \int\ {x}e^{-x}\, dx=-xe^{-x}+\int\ {e^{-x}} \, dx=-xe^{-x}-e^{-x}

∴ V = 8\pi \int\limits^1_0 ({xe^{x}-xe^{-x})} \, dx=8\pi[xe^{x}-e^{x}+xe^{-x}+e^{-x}] from 0 to 1

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∵ e^{-1}=\frac{1}{e}

∴ V=\frac{16\pi}{e}

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torisob [31]
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