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Gemiola [76]
3 years ago
8

What is 5 1/2% simplified as a fraction in simplistic form

Mathematics
1 answer:
zzz [600]3 years ago
8 0

Answer:

11/200

Step-by-step explanation:

=5.5%

=5.5/100

=55/1000

=55/5

------------

1000/5

= 11/200

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Can you find x I don’t know how.
kodGreya [7K]

Answer:

7

Step-by-step explanation:

(x+3)/(x+8) = 2/3

3x + 9 = 2x + 16

x = 7

8 0
3 years ago
10 children equally share 40 almonds <br> How many almonds will 3 children get
pochemuha
The answer is 12

Explanation:

First for this you need to find out how much each child gets

(40 divided by 10)
Each child gets 4 almonds.

If 3 children put their almonds together they will have 12.

(3 times 4)

Brainliest my answer if it helps you out
3 0
2 years ago
A game consists of randomly choosing a bag (labelled 1, 2 or 3) out of a choice of 100, and then again randomly, picking a ball
Scorpion4ik [409]

Answer:

the answer is 112

Step-by-step explanation:

8 0
3 years ago
What fraction of 3 1/2 is 1 1/6
FinnZ [79.3K]
For the first one its 7/2 and the second one is 7/6 
and u cant covert them into a proper fraction you can only covert them into a improper fracion 
7 0
3 years ago
Is the point (16,20) on line ℓ?<br><br><br>​
kicyunya [14]

Answer:

YES

Step-by-step explanation:

Find the equation of the line written as, y = kx. The graph shows a proportional relationship between y and x.

Constant of proportionality/unit rate/slope (k) = rise/run = ⁵/4.

Substitute ⁵/4 in y = kx

We would have:

y = ⁵/4x.

Using the equation of the line, we can know if a given point is on the line by plugging the value of x and y coordinates of the point into the equation. If it makes the equation true, then it is a point on the line. If it doesn't make the equation true, then it isn't a point on the line.

Let's plug in (16, 20) into y = ⁵/4x.

Thus substitute x = 16 and y = 20, we have:

[tex] 20 = \frac{5}{4}(16) [/trex]

[tex] 20 = (5)(4) [/trex]

[tex] 20 = 20 [/trex]

It makes the equation true. Therefore, the point, (16, 20) is a point on line l.

7 0
2 years ago
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