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Gemiola [76]
3 years ago
8

What is 5 1/2% simplified as a fraction in simplistic form

Mathematics
1 answer:
zzz [600]3 years ago
8 0

Answer:

11/200

Step-by-step explanation:

=5.5%

=5.5/100

=55/1000

=55/5

------------

1000/5

= 11/200

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Can someone help me out with this?
dybincka [34]

1/8 + 1/4

the least common multiple of 8 and 4 is 8. Convert 1/8 and 1/4 to fractions with denominator 8.

1/8 + 2/8

Because 1/8 and 2/8 have the same denominator, add them by adding their numerators.

1+2/8

add 1 and 2 to get 3

3/8 or 0.375

4 0
3 years ago
Please help! i literally suck at geometry
sdas [7]
Don’t say like that!Think you can and you will achieve! :) :)
8 0
2 years ago
Express the repeating decimal 2.7 as a fraction.
sergeinik [125]
2/9 is the answer broski
8 0
2 years ago
What is the sum of the answers to the eqation?<br><img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20-%206x%20%2B%205%2
MAVERICK [17]

Answer:

6

Step-by-step explanation:

x^{2} - 6x +5 = 0

x^{2} - 6x + 9 -9 +5 = 0

[x^{2} - 6x + 9] - 4 =0

(x -3)^{2} -4 = 0

(x -3)^{2} = 4

(x-3) = \sqrt{4} or (x-3) = - \sqrt{4}

(x-3) = 2 or (x-3) = -2

x = 5 or x = 1

therefore, sum of these solutions is 5+1 = 6

4 0
3 years ago
Read 2 more answers
A golf tournament has five rounds. The players are given scores for each round based on how many strokes they are above or below
frozen [14]

We have the following table:

Round Number of Strokes Above or Below 72

1 -5

2 +6

3 -2

4 -4

5 +5

So, the expression that represents the total number of strokes is:

72 + (Number of strokes Above or below 72)

Therefore, for every round we get:

Round Number of Strokes Above or Below 72 Total number of strokes

1 -5 72 - 5 = 67

2 +6 72 + 6 = 78

3 -2 72 - 2 = 70

4 -4 72 - 4 = 68

5 +5 72 + 5 = 77

The total number of strokes is:

67 + 78 + 70 + 68 + 77 = 360

Additionally, the average is the total number of strokes divided by the number of rounds, so it is equal to:

\frac{360}{5}=72

Answer: Total: 360 Strokes

Average: 72 Strokes

6 0
1 year ago
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