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WINSTONCH [101]
3 years ago
13

Weatherstripping prevents heat loss by

Physics
2 answers:
kherson [118]3 years ago
6 0
Weatherstripping prevents heat loss by <span>reducing convection and conduction. The correct option among all the options that are given in the question is the second option or option "b". I hope that this is the answer that you were looking for and the answer has actually come to your desired help.</span>
nekit [7.7K]3 years ago
6 0

Answer:

?

Explanation:

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Vector question,university physics zemanski
just olya [345]

Answer:

yes This is correct Answer

3 0
3 years ago
If a football player does 39000 J of work, how much power does the football player exert in 5 minutes
Drupady [299]

Answer:

Power = 130 watt

Explanation:

Power is described as the ability to do work, it is also defined as the amount of work in Joules done in a given time in seconds. Mathematically, it is represented as:

power = \frac{work (J)}{Time (s)}

In this example, power is calculated as follows:

Work = 39000 J

Time = 5 minutes

converting the time from minutes to seconds:

1 minute = 60 seconds

∴ 5 minutes = 60 × 5 = 300 seconds

\therefore power = \frac{39000}{300} \\power = 130 watt

N:B the unit for power can also be represented as Joules/seconds or J/s or JS⁻¹

6 0
3 years ago
A ball of radius r rolls on the inside of a track of radius R. If the ball starts from rest at the vertical edge of the track, f
meriva

Answer:

v=\sqrt{\dfrac{10g(R-r)}{7}}

Explanation:

Given that

Radius of track = R

Radius of ball = r

The ball can be treated as solid sphere, so

The moment of inertia of ball

I=\dfrac{2}{5}mr^2

When the ball reach at the lowest position then it will have both angular and linear speed.

Condition for  rolling without slipping       v= ωr

Form energy conservation

mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

 v= ωr

I=\dfrac{2}{5}mr^2

mgR=mgr+\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mr^2\omega^2

mg(R-r)=\dfrac{1}{2}mv^2+\dfrac{1}{2}\times \dfrac{2}{5}mv^2

2mg(R-r)=mv^2+\dfrac{2}{5}mv^2

2g(R-r)=\dfrac{7}{5}v^2

v=\sqrt{\dfrac{10g(R-r)}{7}}

3 0
3 years ago
Multiplying or dividing vectors by scalar results in?
Minchanka [31]
You divide sort of the similar but vector is distance and displacement and scalar is just distance
6 0
3 years ago
A net force of Fnet acts on an object, causing the object to accelerate at a rat of 9m/s/s. what is the acceleration rate in a s
Readme [11.4K]

The new acceleration is c) 18m/s/s

Explanation:

Net force, mass and acceleration of an object are related by Newton's second law of motion:

F=ma

where

F is the net force on the object

m is its mass

a is its acceleration

In the first trial of this problem, a net force of F_{net} is applied to the object, causing an acceleration of

a=9 m/s^2

Calling the mass of the object 'm', this means that

F_{net} = ma = 9m [N] (1)

In the second trial, the force applied is 2F_{net}, so we have

2F_{net} = ma'

where a' is the new acceleration. Substituting (1) into the second equation, we find:

2(9m) = ma' \rightarrow a' = 18 m/s^2

This is because the acceleration is directly proportional to the force applied: therefore, if the force applied doubled, the acceleration doubles as well.

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

7 0
3 years ago
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