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<em><u>⇒</u></em>Answer:</h2>
In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.600 m and the acceleration achieved from this position is 1.25 times the acceleration due to gravity, g . How far can they jump? State your assumptions. (Increased range can be achieved by swinging the arms in the direction of the jump.)
Step-by-Step Solution:
Solution 35PE
This question discusses about the increased range. So, we shall assume that the angle of jumping will be as the horizontal range is maximum at this angle.
Step 1 of 3<
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The legs have an extension of 0.600 m in the crouch position.
So, m
The person is at rest initially, so the initial velocity will be zero.
The acceleration is m/s2
Acceleration m/s2
Let the final velocity be .
Step 2 of 3<
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Substitute the above given values in the kinematic equation ,
m/s
Therefore, the final velocity or jumping speed is m/s
Explanation:
might be 140mph, so that is a guess that i just made so plz let me know if im wrong or correct
Answer:
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
Explanation:
Inelastic Collision
Given data
mass of glider A m1= 0.125kg
initial velocity u1=0
final velocity v1= 0.600 m/s
mass of glider B m2= 0.375kg
initial velocity u2=0
final velocity v2=?
We know that the expression for the conservation of momentum is given as
m1u1+m2u2=m1v1+m2v2
since u1=u2=u=0m/s
u(m1+m2)=m1v1+m2v2
substituting we have
0(0.125+0.0375)=0.125*0.6+0.375*v2
0=0.075+0.375v2
0.375v2=-0.075
v2=-0.075/0.375
v2=-0.2m/s
The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction
