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3 years ago

What is the difference between sounds that have the same pitch and loudness?

Physics

2 answers:

eduard3 years ago

8 0

Sounds that have the same pitch and loudness can be differentiated by intensity and tone.

omeli [17]3 years ago

5 0

yeah on edegunity those arn't the options A.the standing wave B.the natural frequency C.the sound quality and the last one D.the resonance D is wrong hope someone finds the actual answer

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You are driving your car, and the traffic light ahead turns red. you apply the brakes for 2.26 s, and the velocity of the car de

Lorico [155]

Let the initial velocity of the car be u.

Final velocity of the car (v) = 5.43 m/s

deceleration (a) = - 2.78 m/s^2

Time taken (t) = 2.26 s

Using the first equation of motion:

v = u + at

u = v - at

$u = 5.43 - (-2.78 \times 2.26)$

u = 5.43 + 6.28

u = 11.71 m/s

Let the car's displacement be x.

Using second equation of motion:

$x = ut + \frac{1}{2}at^2$

$x = 11.71 \times 2.26 - \frac{1}{2} \times 2.78 \times 2.26^2$

x = 26.4646 - 7.0995

x = 19.3651 meters

Hence, the displacement of the car is 19.36 meters

6 0

3 years ago

4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not

vampirchik [111]

The ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

$f = \frac{c}{\lambda}$

where

f is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

$\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz$

For the UVB, the range of wavelength is 280 nm - 320 nm, so

$\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz$

So the ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0

3 years ago

Calculate the pressure of water at the bottom of 6m depth well.( g= 9.8m/s square<br>

Alexeev081 [22]

Answer:

58.8NM-²

Explanation:

The pressure is the product of density,depth(height) and acceleration due to gravity

here the density of water is 1gm-³ it a constant so it not given

pressure= 6×9.8×1

pressure = 58.8NM-²

8 0

3 years ago

All examples involve chemical energy except __________. A. working muscles using food. B. burning a candle. C. coasting downhill

navik [9.2K]

The one that does not involve chemical energy would be : C. Coasting downhill on a bike
This one requires physical energy, To be categorized as chemical energy, the bond of chemical compounds has to be released

Hope this helps

7 0

3 years ago

Read 2 more answers

If the pH of a solution decrease's, is the solution getting more acidic or lees acidic

enyata [817]

Answer:

The solution becomes more acidic.

Explanation:

As the pH of a solution decreases, the concentration of hydrogen ions [H+] increases. Acidic solutions have a higher concentration of hydrogen ions and a lower pH.

I hope this helped. :)

6 0

3 years ago