How could you ensure that all the spectroscopes created the same calibration line and equation? What would you need to be sure i
1 answer:
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Answer:
Explanation:
Hello,
In this case, for a concentration of 0.42 M of benzoic acid whose Ka is 6.3x10⁻⁵ in 0.33 M sodium benzoate, we use the Henderson-Hasselbach equation to compute the required pH:
Whereas the concentration of the base is 0.33 M and the concentration of the acid is 0.42 M, thereby, we obtain:
Regards.
Answer:
NaCl.
Explanation:
In the solution, ZnSe ionizes to and
. Following reaction represents the ionization of ZnSe in solution -
⇄
As we want to increase the solubility of ZnSe, we must decrease the concentration of dissociated ions so that the reaction continues to forward direction.
If we add NaCl to this solution, then we have and
in the solution which will be formed by the ionization of NaCl.
Now, in the solution will react with two
ions to form
as follows -
⇄
Due to this reaction the concentration of will decrease in the solution and more ZnSe can be soluble in the solution.