3-chloropropylamine what is?

To what volume should 25ml of 15m nitric acid be diluted to prepare a 3m solution

Maurinko [17]

We can use the dilution formula to find the volume of the diluted solution to be prepared

c1v1 = c2v2

Where c1 is concentration and v1 is volume of the concentrated solution

And c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting the values in the equation

15 M x 25 mL = 3 M x v2

v2 = 125 mL

The 25 mL concentrated solution should be diluted with distilled water upto 125 mL to make a 3 M solution

6 0

3 years ago

how many kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution?

Lena [83]

Answer: The kilograms of water must evaporate from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

Explanation:

According to the ratio and proportion:

$C_1m_1=C_2m_2$

where,

$C_1$ = concentration of ist solution = 25%

$m_1$ = mass of ist solution = 8 kg

$C_2$ = concentration of second solution = 40%

$m_2$ = mass of second solution = ? kg

$25\times 8=40\times m_2$

$m_2=5kg$

Thus the final solution must have a mass of 5 kg , i.e (8-5)= 3 kg of mass must be evaporated.

Therefore, the mass that must be evaporated from 8kg of a 25% salt solution to produce 40% salt solution is 3 kg.

6 0

3 years ago

If the rock has a mass of 250.8 grams, what is its density?

cluponka [151]

To know the density you also need to know the volume of the rock.

4 0

3 years ago

People take antacids, such as milk of magnesia, to reduce the discomfort of acid stomach or heartburn. The recommended dose of m

Llana [10]

Answer:

$V_{HCl}=0.208L=208mL$

Explanation:

Hello,

In this case, since the chemical reaction is:

$2HCl+Mg(OH)_2\rightarrow MgCl_2+2H_2O$

We can see that hydrochloric acid and magnesium hydroxide are in a 2:1 mole ratio, which means that the neutralization point, we can write:

$n_{HCl}=2*n_{Mg(OH)_2}$

In such a way, the moles of magnesium hydroxide (molar mass 58.3 g/mol) in 500 mg are:

$n_{Mg(OH)_2}=500mg*\frac{1g}{1000mg}*\frac{1mol}{58.3g} =0.00858mol$

Next, since the pH of hydrochloric acid is 1.25, the concentration of H⁺ as well as the acid (strong acid) is:

$[H^+]=[HCl]=10^{-pH}=10^{-1.25}=0.0562M$

Then, since the concentration and the volume define the moles, we can write:

$[HCl]*V_{HCl}=2*n_{Mg(OH)_2}$

Therefore, the neutralized volume turns out:

$V_{HCl}=\frac{2*0.00858mol}{0.0562\frac{mol}{L} }\\ \\V_{HCl}=0.208L=208mL$

Best regards.

3 0

3 years ago

Propanoic acid (propionic acid) has the formula CH3CH2COOH. Draw the conjugate base, that is, the structure that results from de

devlian [24]

Answer:

Conjugate base: Propionate

Explanation:

Conjugate base contains one less proton as compared to it's parent acid. Deprotonation occurs from most acidic region.

Propionic acid deprotonates to produce it's strong conjugate base propionate.

In propionic acid, -OH group in -COOH functional moiety dissociates to produce $H^{+}$ . Because the O-H bond electrons remains highly polarized towards oxygen atom due to electron withdrawing inductive effect as well as resonating effect of -COOH moiety.

Structure of conjugate base has been shown below.

7 0

3 years ago