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balu736 [363]
3 years ago
9

Which expression would be easy to simplify if you used the associative property to change the grouping

Mathematics
1 answer:
daser333 [38]3 years ago
7 0
What are the expressions?
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Graph y=2/5x, use x as -2,-1,0,1,2
Natali [406]

Plot a graph of y-axis against x-axis.

The graph should be a straight line passing through:

(-2,0.8) , (-1,-0.4) , (0,0) , (1,0.4) and (2,0.8)

4 0
3 years ago
Determine both the x and y intercepts. Please help! Will mark brainliest!
Mademuasel [1]

Answer:

y-intercept: (0, 2.5)

x-intercept: (1.67, 0)

Step-by-step explanation:

Right now, you have 3x + 2y = 5. You want to change it into slope-intercept form to make the problem easier to solve.

2y = -3x + 5

y = -3/2x + 5/2

From here, you can see that the y-intercept is (0, 5/2). You can also say that the y-intercept is (0, 2.5).

To get the x-intercept, substitute 0 for y.

0 = -3/2x + 5/2

3/2x = 5/2

3x = 5

x = 5/3

So, the x-intercept is (5/3, 0). You can also say that the x-intercept is (1.67, 0).

Hope this helps!

3 0
3 years ago
Read 2 more answers
What is 834% expressed as a fraction?
svetoff [14.1K]

Answer:

8.34/1

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
PLEASE HELP ITS DUE SOON IM SO CONFUSED! HELP NEEDED!!
ddd [48]

Answer:

<u>e</u>

Step-by-step explanation:

According to Angle Sum Property :

<u>∠A + ∠B + ∠C = 180°</u>

<u />

============================================================

Given :

⇒ ∠A = 50°

⇒ ∠B = 32°

===========================================================

Solving :

⇒ 50° + 32° + ∠C = 180°

⇒ ∠C + 82° = 180°

⇒ ∠C = <u>98°</u>

6 0
2 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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