All categories

2 years ago

Find the slope of this line.

Mathematics

1 answer:

natulia [17]2 years ago

4 0

Answer:

4/5

Step-by-step explanation:

SImply use slope formula. We see the graph has defined points at (5, 4), and (-5, -4).

m=(Y2-Y1)/(X2-X1)

(4-(-4))/(5-(-5))=8/10

Simplify 8/10

=4/5

You might be interested in

Which could be used to solve this equation? 3 and one-fifth + n = 9 Subtract 3 and one-fifth from both sides of the equation. 3

dybincka [34]

Answer:

Subtract $3\frac{1}{5}$ from both sides.

Step-by-step explanation:

We want to isolate the variable $n$ . To do this, we have to get rid of $3\frac{1}{5}$ , which we can do by subtracting itself, since it equals 0.

$3\frac{1}{5} + n =9$

$n = 5\frac{4}{5}$

8 0

3 years ago

Which graph shows the solution to the equation below? log Subscript 3 Baseline (x + 3) = log Subscript 0.3 (x minus 1) On a coor

Effectus [21]

Answer:

On a coordinate plane, 2 curves intersect at (1, 1). One curve curves up and to the right from quadrant 3 into quadrant 1. The other curve curves down from quadrant 1 into quadrant 4

Step-by-step explanation:

The first function is given as:

$log_3(x+3)$

The second function is given as:

$log_{0.3}(x-1)$

First we graph both the functions.

We can see that one curves up and to the right from quadrant 3 into quadrant 1. This curve is of $log_3(x+3)$

The other curve curves down from quadrant 1 into quadrant 3

Both curves interest almost at (1,1)

See the graph attached below

Blue line represents first function

Green line represents second function

The solution lies on the Red line.

8 0

3 years ago

Read 2 more answers

The_______ coordinate located at the highest or lowest point on a parobla

djyliett [7]

Answer:

Vertex

Step-by-step explanation:

6 0

3 years ago

Suppose the scores, x, on a college entrance exam are normally distributed with a mean of 500 and a standard deviation of 100. T

Volgvan

Answer:

The minimum score an applicant must receive for admission is 392.

Step-by-step explanation:

Let the minimum score required be 'x₀'.

Given:

Mean score (μ) = 500

Standard deviation (σ) = 100

Percentage required for admission, P > 86% or 0.86

So, we are given the area under the normal distribution curve to the right of z-score which is 86%.

The z-score table gives the area left of the z-score value. So, we will find the z-score value for area 100 - 86 = 14% or 0.14

So, for value equal to 0.1401, the z-score = -1.08

Now, $P(x>x_0)=P(z>-1.08)$

So, we find x₀ using the formula of z-score which is given as:

$z=\frac{x_0-\mu}{\sigma}\\\\-1.08=\frac{x_0-500}{100}\\\\x_0-500=-1.08\times 100\\\\x_0=-108+500=392$

Therefore, the minimum score an applicant must receive for admission is 392.

7 0

3 years ago

Solve -3x=2x^2-4 using quadratic formula

frozen [14]

Answer:

$x=-2.35078, 0.850781$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define equation

-3x = 2x² - 4

Step 2: Rewrite into Standard Form

0 = 2x² + 3x - 4

Step 3: Define variables

a = 2

b = 3

c = -4

Step 4: Find x

Substitute: $x=\frac{-3\pm\sqrt{3^2-4(2)(-4)} }{2(2)}$
Evaluate: $x=\frac{-3\pm\sqrt{9-4(2)(-4)} }{2(2)}$
Multiply: $x=\frac{-3\pm\sqrt{9+32} }{4}$
Add: $x=\frac{-3\pm\sqrt{41} }{4}$
Evaluate: $x=\frac{-3\pm6.40312}{4}$
Evaluate: $x=-2.35078, 0.850781$

And we have our final answer!

6 0

3 years ago