to find the area of a rectangle is LxW=A
plug in the given numbers you have
L = 7
W = x-8
A = 42
7 * x-8 = 42
7x-56= 42
solve for X
Answer:
2x ( x + 5 ) ( x − 2 y )
Step-by-step explanation:
1) factor out 2x from the equation
2) factor out x from the equation
3) factor out -2y from the equation
4) factor out x + 5 from the equation
2x ( x + 5 ) ( x − 2 y )
Answer:
perimeters of the rectangle=p=46.014 metres
Step-by-step explanation:
Given that:
Length (l) = 21 m
Area of rectangle(A) = 42.15 meter-square
Width (w)=?
Required data:
Perimater of Rectangle=p=?
Calculation:
As we know that Area of rectangle=A=l*w
Putting the value we get
42.15 m(square)=(21 m)*w
or w=42.15/21
or w=2.007 m
Now to find perimters of rectangle we know that
p=2(l + w) metres
putting the values
p=2(21+2.007) metres
p=2(23.007) metres
p=46.014 metres
