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baherus [9]
2 years ago
15

Which line has a slope of -1/2? Line A Line B Line C Line D

Mathematics
1 answer:
Alex73 [517]2 years ago
8 0

Answer:

Line D

Step-by-step explanation:

Two points that passes through line D :  (0,-2) & ( -4 , 0)

Slope =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\\=\dfrac{0-[-2]}{-4-0}\\\\\\=\dfrac{0+2}{-4}\\\\\\=\dfrac{2}{-4}\\\\\\=\dfrac{-1}{2}

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If g (x) = -3x + 2 , find g (x + 5).<br><br><br> HELP PLZ
Amanda [17]

Answer:

gx+5g

Step-by-step explanation:

1 Expand by distributing terms.

gx+gx5

2 Regroup terms.

gx+5g

8 0
2 years ago
Find the surface area of this triangular prism Please help is appreciate it
Ad libitum [116K]

Answer: 5,376in.

Step-by-step explanation:

Volume of a prism = Bh

B = 1/2bh

B = 7 x 24 = 168

168 x 32 = 5,376in.

7 0
3 years ago
Consider the circle of radius 5 centered at (0, 0). Find an equation of the line tangent to the circle at the point (3, 4) in sl
Wittaler [7]

Answer:

\displaystyle y= -\frac{3}{4} x + \frac{25}{4}.

Step-by-step explanation:

The equation of a circle of radius 5 centered at (0,0) is:

x^{2} + y^{2} = 5^{2}.

x^{2} + y^{2} = 25.

Differentiate implicitly with respect to x to find the slope of tangents to this circle.

\displaystyle \frac{d}{dx}[x^{2} + y^{2}] = \frac{d}{dx}[25]

\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(y^{2}) = 0.

Apply the power rule and the chain rule. Treat y as a function of x, f(x).

\displaystyle \frac{d}{dx}(x^{2}) + \frac{d}{dx}(f(x))^{2} = 0.

\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}(2f(x)\cdot f^{\prime}(x)) = 0.

That is:

\displaystyle \frac{d}{dx}(2x) + \frac{d}{dx}\left(2y \cdot \frac{dy}{dx}\right) = 0.

Solve this equation for \displaystyle \frac{dy}{dx}:

\displaystyle \frac{dy}{dx} = -\frac{x}{y}.

The slope of the tangent to this circle at point (3, 4) will thus equal

\displaystyle \frac{dy}{dx} = -\frac{3}{4}.

Apply the slope-point of a line in a cartesian plane:

y - y_0 = m(x - x_0), where

  • m is the gradient of this line, and
  • (x_0, y_0) are the coordinates of a point on that line.

For the tangent line in this question:

  • \displaystyle m = -\frac{3}{4},
  • (x_0, y_0) = (3, 4).

The equation of this tangent line will thus be:

\displaystyle y - 4 = -\frac{3}{4} (x - 3).

That simplifies to

\displaystyle y= -\frac{3}{4} x + \frac{25}{4}.

3 0
3 years ago
Pls help I don’t get any of them
JulijaS [17]

Answer:

Step-by-step explanation:

28.   Area of the circle = πr^{2} where r is the radius of the circle.

       Given diameter = 14m, therefore radius = \frac{14}{2} = 7m

       Now area of the circle = 49\pi ^{2} or = 49 * 3.14 * 3.14 = 483.12m^{2}

29. Volume of cylinder = πr^{2}h = π*1.5^{2} * 3 = 6.75π cu. feet or 21.195 cu. feet

30. A ball resembles a sphere. Volume of the sphere = \frac{4}{3} \pi r^{3}

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7 0
3 years ago
a random sample of high school seniors were asked whether they were applying for college. the resulting confidence interval for
Artist 52 [7]

Using the confidence interval, the margin of error is 0.02.

In the given equation we have to find the margin of error.

The resulting confidence interval for the proportion of students applying for college is (0.65,0.69).

Let p = population proportion of students applying for college

P = Sample proportion of students applying for college

ME = margin of error

So the confidence interval

CI = (P-ME, P+ME)

From the given question;

(P-ME, P+ME) = (0.65,0.69)

So lower bound= P-ME = 0.65............................(1)

Upper Bound = P+ME = 0.69............................(2)

Simplifying the Equation 1 and 2

Add equation 1 and 2 we get

2P = 1.34

Divide by 2 on both side we get

P = 0.67

Putting the value of P in the equation 2

P+ME = 0.69

0.67+ME=0.69

Subtract 0.67 on both side we get

ME = 0.02

Hence, the margin of error is 0.02.

To learn more about margin of error link is here

brainly.com/question/10501147

#SPJ4

3 0
1 year ago
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