Answer:
(a) Barium is produced at the negative electrode
(b) Iodine is produced at the positive electrode
Explanation:
When an electric current is passed through a solution containing electrolyte, a non spontaneous reaction is stimulated. This results in the flow of <u>positively charged ions to negatively charged electrodes(</u><u>cathode</u><u>) and negatively charged ions to positively charged electrodes(</u><u>anode</u><u>)</u>
When an electric current is passed through molten 
in the electrolytic cell, the following reactions takes place:
→ 
+ 2
At the anode;
Iodine ions will lose an electron and will be oxidized to iodine
→ 
+ 
At the cathode;
Barium ions gains electrons and its reduced to barium metal
+ 
→ Ba
Answer:
6 days
Explanation:
The following data were obtained from the question:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Half life (t½) =?
Next, we shall determine the decay constant. This can be obtained as follow:
Original amount (N₀) = 100 mg
Amount remaining (N) = 6. 25 mg
Time (t) = 24 days
Decay constant (K) =?
Log (N₀/N) = kt / 2.303
Log (100/6.25) = k × 24 / 2.303
Log 16 = k × 24 / 2.303
1.2041 = k × 24 / 2.303
Cross multiply
k × 24 = 1.2041 × 2.303
Divide both side by 24
K = (1.2041 × 2.303) / 24
K = 0.1155 /day
Finally, we shall determine the half-life of the isotope as follow:
Decay constant (K) = 0.1155 /day
Half life (t½) =?
t½ = 0.693 / K
t½ = 0.693 / 0.1155
t½ = 6 days
Therefore, the half-life of the isotope is 6 days
<span>If a solution conducts electricity, it it positive evidence that solute dissolved in solvent is electrolyte.</span>
(a) The heat generated in the process is 28 kJ.
(b) The work done in the process is determined as -28 kJ.
(c) The change in the internal energy is 0.
<h3>
Heat of the isothermal compression </h3>
The heat generated in the process is negative done in the process.
W = -PΔV
W = -P(V₂ - V₁)
<h3>From A to B</h3>
W = -P(VB - VA)
W = -11(7 - 12.5)
W = 60.5 L.atm = 60.5 x 101.325 J/L.atm = 6,130.16 J
<h3>From C to D</h3>
W = -25(20.5 - 7)
W = -337.5 L.atm = -34,197.18 J
Total work , w = -34,197.18 J + 6,130.16 J = -28 kJ
q = - w
q = 28 kJ
<h3>Change in internal energy</h3>
ΔE = q + w
ΔE = 28 kJ - 28 kJ = 0
Learn more about change in internal energy here: brainly.com/question/17136958
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