<span>a.655 k not 100 percent on this but try it. You will use 273.15 and add your Celcius temp to get it in Kelvin
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Mole = mass / molar mass
123/138.6 = 0.8874
Mr=
K - 39.1
Cl- 35.5
O4 - (16x4= 64).
39.1+35.5+64 = 138.6
Answer:
Empirical formula is C₃H₄O
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of atoms of different elements in small whole number
.
Given data:
Percentage of hydrogen = 7.14%
Percentage of carbon = 64.3%
Percentage of oxygen = 28.6%
Empirical formula = ?
Solution:
Number of gram atoms of H = 7.14 / 1.01 = 7.1
Number of gram atoms of O = 28.6 / 16 = 1.8
Number of gram atoms of C = 64.3 / 12 = 5.4
Atomic ratio:
C : H : O
5.4/1.8 : 7.1/1.8 : 1.8/1.8
3 : 4 : 1
C : H : O = 3 : 4 : 1
Empirical formula is C₃H₄O.
An antacid that lowers the amount of stomach acid
Answer:
The answer to your question is in the attachment
Explanation:
I draw it.