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4 years ago

13

Jason bought a new fish aquarium (shown below) and filled it with water half way. What is the volume of water that Jason put in

his aquarium?

1 answer:

Doss [256]4 years ago

6 0

Answer:

Step-by-step explanation:

The volume is Halfway

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a cook needs 12 pounds of flour he wants to spend the least amount of money if a 2 pound bag costs $1.59 and a 5 pound bag costs

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He should buy two 5 pound bags and one 2 pound bag.

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3 years ago

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While hiking, Sanjay went up 200 meters. If Sanjay started at 500 meters above sea level, which integers represents his elevatio

Aliun [14]

Answer:300

Step-by-step explanation:

-200+500=300

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3 years ago

Can someone help me out with these two problems having trouble please !!

eimsori [14]

Answer:

1.

x=-10

x=-6

2.

x=10

x=-3

Step-by-step explanation:

to find the zeros of a function you need to set it equal to zero:

x^2+16x+60=0

then you factor

(x+10)(x+6)=0

then you have to finish factoring/simplifying

x+10=0

-10

x=-10

x+6=0

-6

x=-6

and the same thing for number 2

x^2-7x-30=0

(x-10)(x-3)=0

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3 0

2 years ago

Read 2 more answers

Help me please , I get it to look forward sorrryyy

Blababa [14]

Step-by-step explanation:

to find mean

add all numbers, then divide by how many set they given

to find median

you need to arrange them ascending order

then what is the number in the middle

to find mode

find what most repeated number

6 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago