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abruzzese [7]
3 years ago
7

Please do first question AND HURRY.

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
5 0
The picture is cut off. We can't solve :/
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What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x​
S_A_V [24]

Answer:

f(g(x))=16x^2+6x-4

Step-by-step explanation:

f(g(x))=4(2x)^2 +3(2x)-4

f(g(x))=16x^2+6x-4

8 0
3 years ago
What is the value of x?
Oduvanchick [21]

Answer:

x = 19

Step-by-step explanation:

Vertical angles are equal

So

7x - 8 = 6x + 11

7x - 6x = 11 + 8

x = 19

7 0
3 years ago
Is 3 squared times 4 squared equal 12 squared ? Evaluate each side of the equation to explain your answer.
Nikolay [14]

Answer:

Nopes 3²+4²≠12²

Step-by-step explanation:

12²=144

3²+4²=

9+16=25

25≠144

To make it easier to see exactly WHY 3²+4²≠12² you can spread out the numbers in the equation.

(3·3)+(4·4)≠(12·12)

When solving equations you use PEMDAS (Parenthesis Exponents Multiplication Division Addition Subtraction). You have to solve in THAT ORDER.

7 0
3 years ago
Read 2 more answers
EThe graph of a quadratic function passes through the points (6,0) and (p,0). The maximum point
MA_775_DIABLO [31]

Answer:

p = - 5

Step-by-step explanation:

The vertex of the function is (0.5, 30.25 )

Since the roots are (6, 0) and (p, 0) then the axis of symmetry is vertical

with equation x = 0.5

The axis of symmetry passes through the midpoint of the roots, thus

\frac{6+p}{2} = 0.5 ( multiply both sides by 2 )

6 + p = 1 ( subtract 6 from both sides )

p = - 5

6 0
3 years ago
I really need help, struggling. Question is in image. ​
Dominik [7]

Answer:

164

Step-by-step explanation:

Checkpoint 2= -187

Checkpoint 1= -23

The negatives mean how much lower they are from the surface.

To find "how much lower," we need to subtract -23 from -187.

-187-(-23) is the same as -187+23 (2 negatives=1 positive)

-187+23= -164.

However, it's not negative in the answer because by asking how much lower, we don't need to have a negative. "How much lower" is a distance, and a distance is always positive.

5 0
2 years ago
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