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stealth61 [152]
4 years ago
11

To park at the airport, drivers must pay a $4 one time fee and $10 per day. Forrest paid $44 to park. How many days did Forrest

park st the airport math problem
Mathematics
2 answers:
3241004551 [841]4 years ago
7 0

Answer:

4 days

Step-by-step explanation:

Create your equation

10x + 4 = 44

10x = 40

x = 4 days

maria [59]4 years ago
6 0

Answer:

FORREST PARKED FOR 4 DAYS

Step-by-step explanation:

10$ A DAY X 4 DAYS IS 40 + THE 4$ ONE TIME FEE

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Julie's city had a parade last weekend. Of the residents in Julie's city, 90,000 came to the parade and 10,000 did not. What per
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Hello can I have some help with this expand question 4(z+2)+4(z+3)
wel

Step-by-step explanation:

4(z+2)+4(z+3)

=4z+8+4z+12

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4 0
3 years ago
Read 2 more answers
(a) Suppose anxn has finite radius of convergence R and an ≥ 0 for all n. Show that if the series converges at R, then it also c
valina [46]

Answer:

a) See the proof below.

b) \sum \frac{(-x)^n}{n}

Step-by-step explanation:

Part a

For this case we assume that we have the following series \sum a)n x^n and this series has a finite radius of convergence R and we assume that a_n \geq 0 for all n, this information is given by the problem.

We assume that the series converges at the point x= R since w eknwo that converges, and since converges we can conclude that:

\sum a)n R^n < \infty

For this case we need to show that converges also for x=-R

So we need to proof that \sum a_n (-R)^n < \infty

We can do some algebra and we can rewrite the following expression like this:

\sum a_n (-R)^n = \sum (-1)^n a)n R^n and we see that the last series is alternating.

Since we know that \sum a_n x^n converges then the sequence {a_n R^n} must be positive and we need to have lim_{n\to \infty} a^n R^n = 0

And then by the alternating series test we can conclude that \sum a_n (-R)^n also converges. And then we conclude that the power series a_n x^n converges for x=-R ,and that complete the proof.

Part b

For this case we need to provide a series whose interval of convergence is exactly (-1,1]

And the best function for this \frac{(-x)^n}{n}

Because the series \sum \frac{(-x)^n}{n} converges to -ln(1+x) when |x| using the root test.

But by the properties of the natural log the series diverges at x=-1 because \sum \frac{1}{n} =\infty and for x=1 we know that converges since \sum \frac{-1}{n} is an alternating series that converges because the expression tends to 0.

6 0
3 years ago
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