6. Bons grocer wishes to mix some nuts worth 90 cents per pound with some nuts worth $1.60 per pound to make 175 pounds of a mix

Question

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6. Bons grocer wishes to mix some nuts worth 90 cents per pound with some nuts worth $1.60 per pound to make 175 pounds of a mix

ture that is worth $1.30 per pound. How much of each should she use? Include your equation. *

Mathematics

2 answers:

Ivenika [448] · Answer 1 · 2022-01-31T22:17:15+03:00

Answer:

75 pounds and 100 pounds.

Step-by-step explanation:

Given:

Bons grocer wishes to mix some nuts worth 90 cents( $0.9) per pound with some nuts worth $1.60 per pound to make 175 pounds of a mixture that is worth $1.30 per pound.

Question asked:

How much of each should she use?

Solution:

Let there are two types of nuts mixed in the mixture, one is nut A and another is nut B.

As we know:

1 cent = $0.01

90 cents = $0.01 $\times$ 90 = $0.9

Let quantity of nut A mixed = $x\ pound$

Quantity of nut B mixed = $175-x\ pound$

Total quantity of mixture = 175 pounds

Total cost of mixture = Cost per pound $\times$ Total quantity of mixture in pound

= $1.30 $\times$ 175 = $227.5

As mixture is prepared by mixing two types of nuts:-

Cost per pound of nut A $\times$ Quantity mixed + Cost per pound of nut B

$0.9x+1.60(175-x)=227.5\\0.9x+280-1.60x=227.5\\-0.7x+280=227.5\\$

By subtracting both sides by 280

$-0.7x=-52.5$

Minus canceled by minus

$0.7x=52.5\\Dividing\ both\ sides\ by\ 0.7\\x=75\ pound$

Substituting the value:-

Quantity of nut A mixed = $x\ pound$ = 75 pounds

Quantity of nut B mixed = $175-x\ pound$ = 175 - 75 = 100 pounds

Therefore, Bons grocer wishes to mix<u> 75 pounds of nuts worth 90 cents</u> ($0.9) with <u>100 pounds of some nuts worth $1.60 </u>per pound to make 175 pounds of a mixture that is worth $1.30 per pound.