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3 years ago

12

The beginning balance of a credit card account is $500. The monthly interest rate is 0.012. If a payment of $100 is made on the

last day of the month, what is the ending balance?

1 answer:

Nataly_w [17]3 years ago

6 0

It is $100 because if you work it out on paper then you could have on the paper and the answer is 100$

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What is the correct way to write 1,550,000,000 in scientific

Anika [276]

1.55 x10 to the power of 9

9
1.55x10

should look something like that

6 0

3 years ago

a shopping channel shipped 467,023 packaged last year what is a reasonable estimate of the number of packages shipped explain

WITCHER [35]

467,000 because if you round higher to 468,000 it would be to far from the original number and 467,000 is closer.

Hope that made sence!

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3 years ago

Triangle ABC has vertices A(0, 2), B(x, 0), and C(0, -2). Determine the value of x that makes triangle ABC a regular triangle.

Jobisdone [24]

Answer:

$x = \sqrt{12 } = 2 \sqrt{3} \: or \\ x = - \sqrt{12} = - 2 \sqrt{3}$

Step-by-step explanation:

In order for the triangle to be a right one we need every side to be of the same length. see the photo for furyher explanation.

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3 years ago

Please answer both ASAP (middle school) (probability)

lana66690 [7]

Answer:

the first one is 18/32 and the second one is 125 games or 120

Step-by-step explanation:

for the first add all the numbers to get your denominator then add the probability of green aND YELLOW.

for the second you just divide 200 by eight to get 25 then times 25 by 5 to get your anwser

hope this helped :)

7 0

2 years ago

Information on a packet of seeds, which may not be a random sample of seeds, claims that the germination rate is 94%. What's

Evgesh-ka [11]

Answer:

0.1052

Step-by-step explanation:

Given that proportion of germination in the population is 94% =0.94

p = 0.96

Sample size = 220

Std dev of p = $\sqrt{\frac{pq}{n} } \\=0.016$

The probability that more than 96% of the 220 seeds in the packet will germinate

= $P(p\geq 0.96)\\=P(Z\geq \frac{0.96-0.94}{0.016})\\=P(Z\geq 1.25)\\==1-0.8948\\=0.1052$

Assumptions are np and nq >5 and also sample size >220 hence normal

7 0

3 years ago