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DanielleElmas [232]
3 years ago
8

2. Solve the following problems involving simple interest. Recall

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer:

A = $56025

Step-by-step explanation:

Given that,

An investor decides to offer a business owner a $45,000 loan at simple interest of 3.5%  per year.

Principal, P = 45,000

Rate of interest, R = 3.5%

We need to find the total amount the investor will receive when the loan is  repaid after 7 years.

The formula for the simple is given by :

I=\dfrac{PRT}{100}\\\\=\dfrac{45000\times 3.5\times 7}{100}\\\\=\$ 11025

We know that,

Amount = Principal + simple interest

So,

A = 45,000 + 11025

A = $56025

So, the required amount is equal to $56025.

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A cookie recipe calls for 2.5 cups of raisins in order to make 2 dozen
RSB [31]

Answer:7

Step-by-step explanation:

U have to simplfly the thing

7 0
3 years ago
Read 2 more answers
Solve each equation and leave the answer in terms of “i”
almond37 [142]
17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
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x = ±2√2i

19)
x² + 3 = 0
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hope this helps, God bless!
3 0
3 years ago
Shaneya purchased a membership to play basketball at her local gym. The membership costs $450 for the year, plus she pays $10 to
olga55 [171]

Answer:

55

Step-by-step explanation:

So start with the total 1,000

then take the 1,000 and minus it by the 450 year so then you can see how much money you have left for the times that she can go to the gym to play.

1,000 - 450 = 550

Now you 550 dollars because basic math. Then you divide the number you got which the number you got was 550 so 550÷10 you divide it by 10 because the rent is 10 each time.

550 ÷ 10 = <u>55</u>

Now you get 55 so that means she can got to the gym 55 times before she goes over 1,000 dollars!

Hoped this helped. Don't forget a middle school person did this so I bet you could have too!

6 0
3 years ago
Solve this application problem using a system of equations: The Bright College footballteam scored 80 times last season, some on
Goryan [66]

Answer:

\large \boxed{\sf \ \ 69 \ \textbf{touchdowns } 11 \ \textbf{field goals } \ }

Step-by-step explanation:

Hello,

Touchdown is 7 points, field goals is 3 points

Let's note a the number of touchdowns and b the number of field goals, we can write

   (1)    a + b = 80

   (2)    7a + 3b = 516

(2) - 3*(1) gives

7a + 3b - 3(a + b) = 516 - 3*80

<=> 7a + 3b -3a - 3b = 516 - 240 = 276

<=> 4a = 276

<=> a=\dfrac{276}{4}=69

And then from (1) b = 80 - 69 = 11

Hope this helps

4 0
3 years ago
Please help me with this!! It might be very easy for you I will also give brainliest if correct
Nimfa-mama [501]
The answer is always
6 0
3 years ago
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