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Brut [27]
3 years ago
9

(20 points)

Physics
2 answers:
dlinn [17]3 years ago
5 0

Answer:

10 m/s at 53.1 degrees

Explanation:

Amanda [17]3 years ago
3 0

The actual velocity of the airplane is 10 m/s at 53.1 degrees north of west

Explanation:

The actual velocity of the airplane can be found using Pythagorean's theorem: in fact, the velocity of the airplane and the velocity of the wind are perpendicular to each other, so they form the sides of a right triangle, of which the hypothenuse corresponds to the actual velocity.

We have:

- Velocity of the airplane: 6 m/s west

- Velocity of the wind: 8 m/s north

Therefore, applying Pytagorean's theorem, the magnitude of the actual velocity of the plane is:

v=\sqrt{v_1^2+v_2^2}=\sqrt{8^2+6^2}=10 m/s

The direction of the airplane instead  can be found by using:

\theta=tan^{-1}(\frac{v_2}{v_1})=tan^{-1}(\frac{8}{6})=53.1^{\circ}

And the direction is north of west.

Learn more about vector addition here:

brainly.com/question/4945130

brainly.com/question/5892298

#LearnwithBrainly

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Answer:

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