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4 years ago

3. This diagram shows that Al can see the reflections of Ed and Fred in the

Physics

1 answer:

Dvinal [7]4 years ago

3 0

Answer:

Only Cy and Di could see the reflections.

Explanation:

Reflection is a property of light that makes it to travel through its initial path on hitting a plane surface. It is good to note that the angle of the incident ray to the surface is equal to the angle of reflection after hitting the surface. It can generally be classified into diffuse and specular.

A ray of light travels on a straight path, the images of the students are formed due to reflection of light at the plane surface. By ray constructions and observation, it would be observed that only Cy and Di could see the reflections of the four students. This is due to their positions with respect to the reflecting surface.

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3 years ago

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Which of the following has a positive charge and a mass of one?

Dmitrij [34]

Answer:

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Explanation:

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3 years ago

For small amplitudes of oscillation the motion of a pendulum is simple harmonic. Consider a pendulum with a period of 0.550 s Fi

Ivenika [448]

To solve this problem we will use the concepts related to the expression of energy for harmonic oscillator. From our given values we have that the period is equivalent to

$T = 0.55s$

Therefore the frequency will be the inverse of the period and would be given as

$f= \frac{1}{T}$

$f = \frac{1}{0.55}$

$f = 1.82s^{-1}$

The ground state energy of the pendulum is,

$E = \frac{1}{2} hv$

$E = \frac{1}{2}(6.626*10^{-34}J\cdot s)(1.82s^{-1})$

$E = 6.03*10^{-34}J$

The ground state energy in eV,

$E = 6.03 * 10^{-34}J(\frac{1eV}{1.6*10^{-19}J})$

$E = 3.8*10^{-15}eV$

The energy difference between adjacent energy levels,

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4 0

3 years ago

A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second

Komok [63]

Answer:

V = 6.65 [volt]

Explanation:

First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

$P=E/t\\P = 40/30\\P = 1.33[s]$

Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

$P=V*I$

where:

V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

$V = 1.33/0.2\\V = 6.65 [volt]$

8 0

4 years ago

a uniform rule balance on a knife edge at the 55cm mark when a mass of 40g is hung from the 95cm mark. find the weight of the ru

BigorU [14]

Answer:

W = 3.1 N

Explanation:

moments about any convenient point will sum to zero.

I choose summing about the knife edge mark and will assume the ruler of weight W is of uniform construction.

I will assume the ruler weight makes a positive moment

W[55 - 50) - 0.040(9.8)[ 95 - 55] = 0

5W = 15.68

W = 3.136

7 0

3 years ago