Answer:
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
Explanation:
Let unknown velocity be v.
Here momentum is conserved.
Initial momentum = Final momentum
Initial momentum = m x 6i + m x 0i = 6m i
Final momentum = m x (4.8cos 30 i + 4.8sin 30 j) + m x v = 4.16 m i + 2.4 m j + m v
Comparing
4.16 m i + 2.4 m j + m v = 6m i
v = 1.84 i - 2.4 j
Magnitude of velocity
Direction,
Velocity is 3.02 m/s at an angle of 53.13° below X-axis.
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This question is wrong because in momontum we will write acceleration instead of speed. suppose acceleration is 5m/s2 then
P= ma
then put values
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