Why would "not flammable" be a chemical property rather than a physical property ?

1 answer:

4 0

When something is flammable, it burns and burning is a chemical property since the compounds are being broken down and gas is released. If something is non-falammable, it would then be a chemical property as well since the chemical makeup would not be broken by a flame. (I apologize if my answer is a bit broad or unspecific)

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Which statement correctly describes soil horizon C? A. It is considered the subsoil layer. B. It is the horizon with the smalles

kirill [66]

Answer:

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Explanation:

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A plutonium atom undergoes nuclear fission. Identify the missing element in the nuclear equation.

horrorfan [7]

Answer:

$_{92}^{226}U$

Explanation:

Let's firstly identify the atomic number (the number of protons) of Pu. This is done by referring to the periodic table and finding Pu. The atomic number of Pu is:

$Z=94$

In order to identify the type of a nuclear decay, we need to find the N/Z ratio. This is the ratio between the number of neutrons and the atomic number of an isotope. The number of neutrons is found by subtracting the number of protons from the mass number:

$N=M-Z$

That said, the N/Z ratio equation becomes:

$N/Z=\frac{M-Z}{Z}=\frac{M}{Z}-1=\frac{230}{94}-1=1.45$

This is a relatively high number thinking about the belt of stability of isotopes. Ideally, stable isotopes with a low Z value have an N/Z ratio of 1. Heavier isotopes with Z > 50 would have a slightly higher N/Z ratio and would be stable around N/Z = 1.25. This means we wish to decrease the N/Z ratio as much as possible.

Among all the decays, alpha-decay is preferred to decrease the N/Z ratio significantly (1.45 is much higher than 1.25). That said, we'll release an alpha particle with some nucleotide X of mass M and atomic number Z:

$_{94}^{230}Pu\rightarrow _Z^MX+_2^4\alpha$