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2 years ago

Carbonated drinks in cans have a small amount of space above the liquid level inside the can known as

Chemistry

2 answers:

Verdich [7]2 years ago

7 0

Answer:c

Explanation:

kenny6666 [7]2 years ago

3 0

Answer:

Temperature stays constant.

Explanation:

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The combustion of 0.570 g of benzoic acid (ΔHcomb = 3,228 kJ/mol; MW = 122.12 g/mol) in a bomb calorimeter increased the tempera

torisob [31]

Answer:

The temperature change from the combustion of the glucose is 6.097°C.

Explanation:

Benzoic acid;

Enthaply of combustion of benzoic acid = 3,228 kJ/mol

Mass of benzoic acid = 0.570 g

Moles of benzoic acid = $\frac{0.570 g}{122.12 g/mol}=0.004667 mol$

Energy released by 0.004667 moles of benzoic acid on combustion:

$Q=3,228 kJ/mol \times 0.004667 mol=15.0668 kJ=15,066.8 J$

Heat capacity of the calorimeter = C

Change in temperature of the calorimeter = ΔT = 2.053°C

$Q=C\times \Delta T$

$15,066.8 J=C\times 2.053^oC$

$C=7,338.92 J/^oC$

Glucose:

Enthaply of combustion of glucose= 2,780 kJ/mol.

Mass of glucose=2.900 g

Moles of glucose = $\frac{2.900 g}{180.16 g/mol}=0.016097 mol$

Energy released by the 0.016097 moles of calorimeter combustion:

$Q'=2,780 kJ/mol \times 0.016097 mol=44.7491 kJ=44,749.1 J$

Heat capacity of the calorimeter = C (calculated above)

Change in temperature of the calorimeter on combustion of glucose = ΔT'

$Q'=C\times \Delta T'$

$44,749.1 J=7,338.92 J/^oC\times \Delta T'$

$\Delta T'=6.097^oC$

The temperature change from the combustion of the glucose is 6.097°C.

6 0

2 years ago

Which method can be used to find the range

lidiya [134]

Answer:

To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest

3 0

3 years ago

Read 2 more answers

Flames are the heat and light energy that is release when the chemical bonds in a substance are broken. What provides the chemic

Tpy6a [65]

Answer is C:Wax Or B:Heat

8 0

3 years ago

Read 2 more answers

How many grams of CO 2 are present in a container with a volume of 5.61 L if the gas exhibits a pressure of 5.66 atm at a temper

Kruka [31]

Answer:

54.72 g

Explanation:

Mass = ?

Volume = 5.61 L

Pressure = 5.66 atm

Temperature = 311 K

The relationship between these equations is given by the ideal gas equation;

PV = nRT

where R = gas constant = 0.0821 atm L K-1 mol-1

n = PV / RT

n = 5.66 * 5.61 / (0.0821 * 311 )

n = 1.2436 mol

Number of moles = Mass / Molar mass

Mass = Number of moles * Molar mass = 1.2436 * 44 = 54.72 g

5 0

3 years ago

The higher the number of living organisms in an area, the ___ fertile the soil.<br> Less, more.

goldenfox [79]

I think it is the more fertile the soil

4 0

2 years ago