Answer:
Ni(NO3)2 + 2NaOH → Ni(OH)2 + 2NaNO3
NET IONIC EQUATION :
Ni +2(aq) + 2(NO3) -1(aq) + 2Na +1(aq) + 2OH -1(aq)
→ Ni(OH)2 (s) + 2Na +1(aq) + 2(NO3) -1(aq)
sorry there is no space to write the reaction in one line...
Molarity = 3.9 * 10 ^ -8
pH = - log (3.9 * 10 ^ -8)
pH = - (-7.40893539)
pH = 7.409 = 7.4 ... Ans
PbO
Not sure how to show crisscross method
Make sure adding the charges together=0 and multiply the elements when necessary to balance charge
Answer:
760 mmHg
Explanation:
Step 1: Given data
- Partial pressure of nitrogen (pN₂): 592 mmHg
- Partial pressure of oxygen (pO₂): 160 mmHg
- Partial pressure of argon (pAr): 7 mmHg
- Partial pressure of the trace gas (pt): 1 mmHg
Step 2: Calculate the atmospheric pressure
Since air is a gaseous mixture, the atmospheric pressure is equal to the sum of the gases that compose it.
P = pN₂ + pO₂ + pAr + pt = 592 mmHg + 160 mmHg + 7 mmHg + 1 mmHg = 760 mmHg
