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Zolol [24]
3 years ago
9

What is the new concentration for 25mL added to 135mL of .150M

Chemistry
1 answer:
Airida [17]3 years ago
5 0

Answer:

The concentration for 25 mL is 0.81 M

Explanation:

Given data:

Initial volume = 135 mL

Initial molarity = 0.150 M

New volume added = 25 mL

Concentration for 25 mL = ?

Solution:

M₁V₁    =    M₂V₂

0.150 M × 135 mL = M₂ × 25 mL

M₂ = 0.150 M × 135 mL / 25 mL

M₂ = 20.25 M.mL/25 mL

M₂ = 0.81 M

The concentration for 25 mL is 0.81 M.

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bekas [8.4K]

Answer:

in all green plants and most algae

6 0
4 years ago
A substance with which bond type would have a high melting point?
DaniilM [7]

Answer:

The answer to your question is A. Ionic

Explanation:

There are 3 kinds of bonds in chemistry

a) Ionic bonds are the bonds between a metal and a nonmetal. Metals lost their electrons and nonmetals gain them. These bonds are the strongest so the melting and boiling points are the highest of all.

b) Covalent bonds are bonds between two nonmetals. The elements share electrons so these bonds are not as stronger as Ionic bonds, the melting and boiling points are high.

c) Metallic bonds are among metals and have high melting and boiling points.

7 0
3 years ago
10
MAVERICK [17]

The equilibrium constant (K) : 11.85

<h3>Further explanation</h3>

Given

Reaction

N₂(g) + 3H₂(g) ⇒ 2NH₃(g)

Required

K(equilibrium constant)

Solution

The equilibrium constant (K) is the value of the concentration product in the equilibrium

The equilibrium constant based on concentration (K) in a reaction  

pA + qB -----> mC + nD  

\tt K=\dfrac{[C]^m[D]^n}{[A]^p[B]^q}

For the reaction above :

\tt K=\dfrac{[NH_3]^2}{[N_2][H_2]^3}\\\\K=\dfrac{0.1^2}{0.25\times 0.15^3}\\\\K=11.85

6 0
3 years ago
Why N2 has a lower boiling point than CO?
disa [49]
CO HAS A HIGHER BOILING POINT BECAUSE THE INTEMOLECULAR FORCES ARE STRONGER THEN N2 WHICH IS NON POLAR. CO HAS A HIGHE BOILING POINT BECAUSE THE INTEMOLECULAR FORCES ARE STRONGER THEN N2 WHICH IS NON POLAR
7 0
3 years ago
Number of Ag atoms in .240 mol
Alexus [3.1K]

Answer:

1.445 x 10²³ atoms.

Explanation:

  • It is known that 1.0 mole of any element contains Avogadro's no. (6.022 x 10²³) of atoms.

<u><em>Using cross multiplication:</em></u>

1 mol of Ag contains → 6.022 x 10²³ atoms.

∴ 0.24 mol of Ag contains → <em>??? atoms.</em>

∴ The no. of Ag atoms in 0.24 mol = (0.24 mol)(6.022 x 10²³ atoms)/(1 mol) = 1.445 x 10²³ atoms.

3 0
3 years ago
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