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3 years ago

Find f(-3) for the function f(x)=x^2-8x

Mathematics

2 answers:

abruzzese [7]3 years ago

5 0

Answer:

substitute x= -3

f (-3)=9+24

=33

Andrei [34K]3 years ago

5 0

Answer:

f(-3)=33

Step-by-step explanation:

Substitute -3 in for both x's

f(x)=x^2-8x

f(-3)=(-3^2)-8(-3)

f(-3)=(9)+24

f(-3)=33

Hope this helps! :)

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(a) Draw in radii OA, OB, OC and OD. Then, explain why OAB must

lions [1.4K]

Answer:

In the given circle, segments OA, OB, OC and OD are radius of the circle.

In other words, all those segments are congruent.

From that we can deduct that triangles OAB and OCD are isosceles triangles, because all segments are equal. That makes those triangles congruent, because they have the same sides.

From the congruence we can deduct that all corresponding internal angles inside those triangles are actually congruent, that's why angle OAB and ODC must be congruent.

Also, angles DOC and BOA are also congruent, which means their subtended arcs are also congruent, because they have the same radius, so mAB = mCD.

7 0

3 years ago

in biology class,the girl ratio is 3 to 10.if their are total of 52 students,how many boys are are their?

TEA [102]

Answer:40 boys

Step-by-step explanation:10/3+10 x 52

10/13 x 52=40 boys

3 0

3 years ago

Given that h(x) = 3x −19, find the value of x that makes h(x) = 71.

rosijanka [135]

Keywords:

<em>Equation, variable, value, clear </em>

For this case we have an equation with a variable of the form $y = h (x)$ . Where $h (x) = 3x-19$ . Given the value of $h (x) = 71$ , we want to find the value of the variable "x". So, we have:

$h (x) = 3x-19\\71 = 3x-19$

We must clear "x", for this, we add "19" to both sides of the equation:

$71 + 19 = 3x-19 + 19\\90 = 3x$

We divide between "3" on both sides of the equation:

$\frac {90} {3} = \frac {3x} {3}\\30 = x$

Thus, the value of the variable "x" is 30.

Answer:

$x = 30$

Option A

6 0

3 years ago

Read 2 more answers

The sequence$$1,2,1,2,2,1,2,2,2,1,2,2,2,2,1,2,2,2,2,2,1,2,\dots$$consists of $1$'s separated by blocks of $2$'s with $n$ $2$'s i

kicyunya [14]

Consider the lengths of consecutive 1-2 blocks.

block 1 - 1, 2 - length 2

block 2 - 1, 2, 2 - length 3

block 3 - 1, 2, 2, 2 - length 4

block 4 - 1, 2, 2, 2, 2 - length 5

and so on.

Recall the formula for the sum of consecutive positive integers,

$\displaystyle \sum_{i=1}^j i = 1 + 2 + 3 + \cdots + j = \frac{j(j+1)}2 \implies \sum_{i=2}^j = \frac{j(j+1) - 2}2$

Now,

$1234 = \dfrac{j(j+1)-2}2 \implies 2470 = j(j+1) \implies j\approx49.2016$

which means that the 1234th term in the sequence occurs somewhere about 1/5 of the way through the 49th 1-2 block.

In the first 48 blocks, the sequence contains 48 copies of 1 and 1 + 2 + 3 + ... + 47 copies of 2, hence they make up a total of

$\displaystyle \sum_{i=1}^48 1 + \sum_{i=1}^{48} i = 48+\frac{48(48+1)}2 = 1224$

numbers, and their sum is

$\displaystyle \sum_{i=1}^{48} 1 + \sum_{i=1}^{48} 2i = 48 + 48(48+1) = 48\times50 = 2400$

This leaves us with the contribution of the first 10 terms in the 49th block, which consist of one 1 and nine 2s with a sum of $1+9\times2=19$ .

So, the sum of the first 1234 terms in the sequence is 2419.

8 0

2 years ago

What is the common ratio for the geometric sequence? 32, 8, 2, 12, ... Enter your answer in the box.

mamaluj [8]

Answer:

Given sequence is not a geometric progression and there will be no common ration for this sequence.

Step-by-step explanation:

Need to determine common ration for the following geometric sequence

32, 8, 2, 12, ...

In given geometric sequence

a1 = 32, a2=8, a3=2, a4=12 ……….

Common ratio = $\frac{a_2}{a_1} =\frac{a_3}{a_2} =\frac{a_4}{a_3}$

$\frac{a_2}{a_1}=\frac{8}{32}=\frac{1}{4}$

$\frac{a_3}{a_2} =\frac{2}{8}=\frac{1}{4}$

$\frac{a_4}{a_3}=\frac{12}{2}=6$

Since $\frac{a_2}{a_1}=\frac{a_3}{a_2}\neq\frac{a_4}{a_3}$ so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.

3 0

3 years ago