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Illusion [34]
4 years ago
7

(2x + 3)3 I need help please

Mathematics
2 answers:
AysviL [449]4 years ago
4 0
All u need to do is distribute the 3
(2x+3)3
6x+9
then u can’t do anything else because these terms are not the same and u can’t combine them. hope this helps :)
ivann1987 [24]4 years ago
3 0

Answer:

6x+9

(2x+3)3

you would distribute 3 into 3 and 2x to get...

6x+9

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Nataly_w [17]

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We would like to solve the below <u>quadratic </u><u>equation</u><u> </u>,

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Step 1 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>f</u><u>(</u><u>x</u><u>)</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow f(x) = 0\\

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Step 2 : <u>F</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u>i</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>R</u><u>H</u><u>S</u><u> </u><u>:</u><u>-</u>

\longrightarrow x^2-8x - 4x +32=0\\

\longrightarrow x(x-8)-4(x-8)=0\\

\longrightarrow (x-8)(x-4)=0\\

Step 3 : <u>E</u><u>q</u><u>u</u><u>a</u><u>t</u><u>e</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>f</u><u>a</u><u>c</u><u>t</u><u>o</u><u>r</u><u> </u><u>w</u><u>i</u><u>t</u><u>h</u><u> </u><u>0</u><u> </u><u>:</u><u>-</u>

\longrightarrow x - 8 = 0\\ \qquad x -4=0

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olga_2 [115]
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