The numbers are: "7 " and "21 " .
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Explanation:
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The numbers are: "x" and "x + 14" .
x + (x + 14) = 28 . Solve for "x" ; and then solve for "x + 14" .
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→ x + (x + 14) = 28 ;
Rewrite as:
→ x + x + 14 = 28 ;
→ 1x + 1x + 14 = 28 ;
→ 2x + 14 = 28 ;
Subtract "14" from each side of the equation;
→ 2x + 14 − 14 = 28 <span>− 14 ;
</span> → 2x = 14 ;
Divide EACH SIDE of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 2x / 2 = 14 / 2 ;
→ x = 7 .
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So; one of the numbers is: " 7 " .
The other number is: " x + 14 " ; which equals: " 7 + 14 = 21".
The other number is: "21 " .
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The numbers are: "7 " and "21 " .
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Answer:
B,E and F are your answers
Answer:

Step-by-step explanation:
No it isn't, because:
![{1.08}^{ \frac{1}{5} } = { \frac{108}{100} }^{ \frac{1}{5} } = { \frac{27}{25} }^{ \frac{1}{5} } = \sqrt[5]{ \frac{27}{25} } = 1.01551](https://tex.z-dn.net/?f=%20%7B1.08%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B108%7D%7B100%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%5E%7B%20%5Cfrac%7B1%7D%7B5%7D%20%7D%20%20%3D%20%20%5Csqrt%5B5%5D%7B%20%5Cfrac%7B27%7D%7B25%7D%20%7D%20%20%3D%201.01551)