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Dafna11 [192]
3 years ago
7

Which graph represents the following piecewise defined function?

Mathematics
2 answers:
ehidna [41]3 years ago
7 0

Answer:

3rd graph

Step-by-step explanation:

olga nikolaevna [1]3 years ago
7 0

Answer:

C

Step-by-step explanation:

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The scale on a map that 5 centimeters = 2 kilometers
spin [16.1K]
So that is what we call a ratio and it looks like this
\frac{5cm}{2km} \\
3 0
3 years ago
1.) Which domain restrictions apply to the rational expression? 14x-2x / x^2-7x
mezya [45]

Answer:

3. \displaystyle 1\frac{1}{3} = x

2<em>C.</em> \displaystyle III.

2<em>B.</em> \displaystyle I.

2<em>A.</em> \displaystyle II.

1. \displaystyle Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

Step-by-step explanation:

3. <em>See</em><em> </em><em>above</em>.

2<em>C</em>. The keyword is ratio, which signifies division, so you would choose "III.".

2<em>B</em>. The keyword is percent, which signifies multiplication of a ratio by 100, so you would choose "I.".

2<em>A</em>. The keyword is total, which signifies addition, so you would choose "II.".

1. Base this off of the denominator. Knowing that the denominator CANNOT be zero, you will get this:

\displaystyle x^2 - 7x \\ x[x - 7] = 0; 7, 0 = x \\ \\ Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)

I am joyous to assist you anytime.

5 0
3 years ago
The radius of the base of a cylinder is increasing at a rate of 7 millimeters per hour. The height of the cylinder is fixed at 1
Ilya [14]

Answer:

The rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

Step-by-step explanation:

Given:

Rate of increase of base of radius of base of cylinder = 7 mm/hr

Height of cylinder = 1.5 mm

Radius at a certain instant = 12 mm

To find rate of change of volume of cylinder at that instant.

Solution:

Let r represent radius of base of cylinder at any instant.

Rate of increase of base of radius of base of cylinder can be given as:

\frac{dr}{dt}=7\ mm/hr

Volume of cylinder is given by:

V=\pi\ r^2h

Finding derivative of the Volume with respect to time.

\frac{dV}{dt}=\pi\ h\ 2r\frac{dr}{dt}

Plugging in the values given:

\frac{dV}{dt}=\pi\ (1.5)\ 2(12)(7)

\frac{dV}{dt}=252\pi

Using \pi=3.14

\frac{dV}{dt}=252(3.14)

\frac{dV}{dt}=791.28\ mm^3/hr (Answer)

Thus rate of change of the volume of the cylinder at that instant = 791.28\ mm^3/hr

6 0
3 years ago
1. What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4), and D(5,2)?
zaharov [31]
The first one is B because of the first attachment. The second one is A because of the second attachment. The third one is C because of the expression used to solve for sum of angles: 
(n-2)180 
(8-2)180
1080
Hope this helps!

7 0
3 years ago
Read 2 more answers
A store diplays will have 6 rows,12 contaners in each row.if 39 contaners has been set UPS so farsa explain how to find the numb
torisob [31]
Multiply:
6•12=72

Then, you subtract 39 from 72:
72-39=33

33 containers would still need to be set up.
4 0
3 years ago
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