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Snezhnost [94]
4 years ago
12

What is the general equation of a sine function with an amplitude of 2, a period of pi and a horizontal shift of pi units?

Mathematics
2 answers:
joja [24]4 years ago
8 0

Answer:

The general form of the sine function is y=2\sin(2(x-\pi))

Explanation:

The general form of a sinusoidal function is in the form

y=A\sin(B(x-C))+D

Here, A = amplitude

C = Horizontal shift

D = Vertical shift or mid line

The formula for finding the period is P=\frac{2\pi}{B}

Further Explanation:

It has been given that, the amplitude is 2. Thus, A = 2

Now, the period is π. Thus, we can use the formula for period for finding the value of B.

P=\frac{2\pi}{B}\\\\\pi=\frac{2\pi}{B}\\\\B=2

Therefore, the value of B is 2.

Now, since the variable c is phase shift or horizontal shift and it has been given that horizontal shift is π units.

Thus, C = π

Therefore, the general form of the sine function is

y=2\sin(2(x-\pi))

Learn More:

brainly.com/question/5470844 (Answered by Eudora)

brainly.com/question/7280065 (Answered by Merlynthewhizz)

Keywords:

  • general form  sinusoidal functions
  • Sinusoidal graphs
  • Amplitude and period of sinusoidal functions
Talja [164]4 years ago
6 0
Y= (amplitude).sin(2π/period).(x-shift)

= 2.sin(2π/π)(x-π)


=2.sin[2.(x-π)]
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