G^−m ÷ g^n
1st g^−m=1/g^m, hence g^−m ÷ g^n = (1/g^m) /(g^n)==> 1/(g^m)(g^(n)
==> 1/(g^m+n) or g^(-m-n)
Part b is $638.40
Part c is $1,641.6
Answer: 0.62
Step-by-step explanation:
Total people= 47
Let A be the event of selecting person was interested in trying the new drink.
Person not interested in trying a sample of a new soft drink (nA')=18
Person interested in trying a sample of a new soft drink (nA)=47-18=29
Thus probability that a randomly selected person was interested in trying the new drink
P (A) = 29/41 = 0.6170 (or) 0.62
Thus, probability that a randomly selected person was interested in trying the new drink is 0.62.
47-18=29 people interested in the new drink
29/47=0.617
0.617*100=61.7% chance
Answer:
Y=(4x)^3
Y=64x^3
Step-by-step explanation:
Y=(3√x)÷4
Making X subject of formula
4y= (3√x)
(4y)^3= (3√x)^3
(4y)^3 = X,
Replacing Y with X
Y=(4x)^3
Y=64X^3
Step-by-step explanation:
each child gets a certain amount of items costing the specified price by item.
so, we need to multiply the number of children with the number of items with the price per item to get the total cost.
500×3×3.5 for pencils = 5,250
500×5×7.5 for notebooks = 18,750
500×1×21.75 for crayons = 10,875
500×2×9.26 for pad paper = 9,260
total 44,135
since we have only 1,200 available in the existing fund, we need a new one to cover the remaining
44,135 - 1,200 = 42,935
