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4 years ago

15

Multiply. Simplify by combining like terms. (m+11N)^2

1 answer:

Aloiza [94]4 years ago

4 0

(m+11n)^2
=(m+11n)(m+11n)
=m^2+11mn+11mn+121n^2
=m^2+22mn×121n^2

For Example;

use FOIL: (a+b)(a+b)

First. a^2
Outside. ab
Inside. ab
Last. b^2

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The next number in the arithmetic sequence 15, 22, 29, is: <br><br>A) 34<br>B) 35<br>C) 36<br>D) 37

harkovskaia [24]

ANSWER: C) 36
EXPLANATION: +7 is the sequence

4 0

2 years ago

Find the equation of the line that passes through (–3, 2) and the intersection of the lines x–2y=0 and 3x+y+5=0.

ipn [44]

Answer:

$\frac{19}{7}$ x+ $\frac{11}{7}$ y+5=0

Step-by-step explanation:

the intersection of x-2y=0 and 3x+y+5 is ( $\frac{-10}{7}$ ; $\frac{-5}{7}$ )

=> the line : $\frac{19}{7}$ x+ $\frac{11}{7}$ y+5=0

7 0

3 years ago

Read 2 more answers

7/10x4/5 in its simplest form

Fantom [35]

Answer:

14/25

Step-by-step explanation:

7/10 x 4/5

28/50

14/25

8 0

4 years ago

(9x5)x10to the 4th power

WARRIOR [948]

$(9\times 5) \times 10^4 = 20 \times 10,000 = 200,000$

So 200,000 is your answer :)

7 0

3 years ago

The coordinates of the vertices of a rectangle are (−3, 4) , (7, 2) , (6, −3) , and (−4, −1) . What is the perimeter of the rect

ki77a [65]

Answrer

Find out the what is the perimeter of the rectangle .

To prove

Now as shown in the figure.

Name the coordinates as.

A(−3, 4) ,B (7, 2) , C(6, −3) , and D(−4, −1) .

In rectangle opposite sides are equal.

Thus

AB = DC

AD = BC

Formula

$Disatnce\ formula = \sqrt{(x_{2} - x_{1})^{2} +(y_{2} - y_{1})^{2}}$

Now the points A(−3, 4) and B(7, 2)

$AB = \sqrt{(7- (-3))^{2} +(2- 4)^{2}}$

$AB = \sqrt{(10)^{2} +(-2)^{2}}$

$AB = \sqrt{100+4}$

$AB = \sqrt{104}$

$AB = 2\sqrt{26}\units$

Thus

$CD= 2\sqrt{26}\units$

Now the points

A (−3, 4) , D (−4, −1)

$AD = \sqrt{(-4 - (-3))^{2} +(-1- 4)^{2}}$

$AD = \sqrt{(-1)^{2} +(-5)^{2}}$

$AD = \sqrt{1 + 25}$

$AD = \sqrt{26}\units$

Thus

$BC = \sqrt{26}\units$

Formula

Perimeter of rectangle = 2 (Length + Breadth)

Here

$Length = 2\sqrt{26}\ units$

$Breadth = \sqrt{26}\ units$

$Perimeter\ of\ rectangle = 2(2\sqrt{26} +\sqrt{26})$

$Perimeter\ of\ rectangle = 2(3\sqrt{26})$

$Perimeter\ of\ rectangle = 6\sqrt{26}$

$\sqrt{26} = 5.1 (Approx)$

$Perimeter\ of\ rectangle = 6\times 5.1$

Perimeter of a rectangle = 30.6 units.

Therefore the perimeter of a rectangle is 30.6 units.

8 0

3 years ago