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PSYCHO15rus [73]
4 years ago
5

Find the equation of the line. Use exact numbers.

Mathematics
1 answer:
GarryVolchara [31]4 years ago
6 0

Answer:

y = $ \frac{1}{2} $x - 3

Step-by-step explanation:

Let the general equation of the line be y = ax + b

Note that the points (6,0) and (0,-3) lie on the line. That means, it should satisfy the equation of the line. We substitute the points on the equation of the line.

We would have:

$ 0 = 6a + b \hspace{25mm} ...(1) $

$ -3 = a(0) + b \hspace{20mm} ....(2) $

From (2), we get: b = -3

From (1), we have -6a = b

Substituting b = -3, we get:

-6a = -3

⇒ a = 1/2

Therefore, the equation of the line would become: y = 1/2x - 3

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May someone pls assist me on this question
Arada [10]

Answer:

x=-4 or x=-8

Step-by-step explanation:

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5 0
1 year ago
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We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the stu
Molodets [167]

Answer:

The correct option is (c).

Step-by-step explanation:

The complete question is:

The data for the student enrollment at a college in Southern California is:

                    Traditional          Accelerated            Total

                  Math-pathway     Math-pathway

Female              1244                       116                   1360

Male                  1054                       54                    1108

Total                  2298                     170                  2468

We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?

a. 1360/2468 and 116/170

b. 170/2468 and 116/1360

c. 1360/2468 and 170/2468

Solution:

If two events <em>A</em> and <em>B</em> are independent then:

P(A|B)=P(A)\\\\\&\\\\P(B|A)=P(B)

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.

Consider the following probabilities:

P (F|A) = \farc{116}{170}\\\\P(A|F)=\frac{116}{1360}\\\\P(A)=\frac{170}{2468}\\\\P(F)=\frac{1360}{2468}

If the two events are independent then:

P (F|A) = P(F)

&

P (A|F) = P (A)

But what would not be a valid comparison is:

P (A) = P(F)

Thus, the correct option is (c).

4 0
3 years ago
42 67 68 70 71 78 79 80 81 84 86 86 89 99 99<br>calculate the five number summary ​
Step2247 [10]

Answer:

Min - 42

Max - 99

M = 80

Q1 = 70

Q3 = 86

Step-by-step explanation:

The five-number summary is a descriptive statistic that provides information about a set of observations. It consists of the minimum, maximum, median, first quartile, and third quartile.

5 0
2 years ago
-8x-2y=6 in slope form
Harrizon [31]
Perhaps you mean "slope-intercept" form. Solve for y and reduce the fractions.
.. -8x -6 = 2y . . . . . . . . add 2y-6
.. y = -4x -3 . . . . . . . . . divide by 2

Your line in slope-intercept form is
.. y = -4x -3
4 0
3 years ago
3<br>Find the value of a <br>in the equation,(3+4√3)(2-a√3)=-18+2√3​
ankoles [38]

Given:

The equation is:

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

To find:

The value of a.

Solution:

We have,

\left(3+4\sqrt{3}\right)\left(2-a\sqrt{3}\right)=-18+2\sqrt{3}

On simplification, we get

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6+8\sqrt{3}-3a\sqrt{3}-12a=-18+2\sqrt{3}

(6-12a)+(8-3a)\sqrt{3}=-18+2\sqrt{3}

On comparing both sides, we get

6-12a=-18

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And,

8-3a=2

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a=\dfrac{-6}{-3}

a=2

Therefore, the value of a is 2.

3 0
3 years ago
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