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AfilCa [17]
3 years ago
14

How do i solve 0 = x squared + 3​

Mathematics
2 answers:
My name is Ann [436]3 years ago
7 0

Answer:

3

Step-by-step explanation:

0•0=0

0+3=3

Georgia [21]3 years ago
7 0

Answer:

x= -1.73

Step-by-step explanation:

0 = x²+3

subtract 3 from both sides

0-3 = x²+3-3

-3 = x²

square root both sides to make x the subject of the formula

√-3 = √x²

square cancel the square root

∴ x= -1.73

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QveST [7]
For example: if there are two tens and 15 ones, you could take another ten out of the ones. this makes the adding less complicated
7 0
2 years ago
For what value of x do the expressions 2x+3 and 3x+-6 have the same value?
Black_prince [1.1K]
The answer is 2 because it’s -6/3 =2
3 0
3 years ago
Read 2 more answers
The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:
Marina CMI [18]
<h2>Answer:</h2>

The tangent, cotangent, and cosecant functions are odd , so the graphs of these functions have symmetry with respect to the:

                                 Origin.

<h2>Step-by-step explanation:</h2>

A function f(x) is said to be a odd function if:

                    f(-x)=-f(x)

Also, an odd function always has a symmetry with respect to the origin.

whereas a function f(x) is said to be a even function if:

                      f(-x)=f(x)

Also, an even function has a symmetry with respect to the y-axis.

We know that:

Tangent function, cotangent function and cosecant function are odd functions.

Since,

\tan(-x)=-\tan x\\\\\cos (-x)=-\cot x\\\\\csc (-x)=-\csc x

( similarly sine function is also an odd function.

whereas cosine and secant function are even functions )

<em>Hence, the graph of tangent function, cotangent function and cosecant function  is symmetric about the origin.</em>

7 0
3 years ago
Solve for the unknown in the following diagram. Round the answer to two decimal places.<br>in<br>​
Alexxandr [17]

Answer:

172.27 in

Step-by-step explanation:

Apply the Sine Rule

Sine Rule is given as:

\frac{a}{sin(A)} = \frac{b}{sin(B)} = \frac{c}{sin(C)}

c = x = ?

C = 180 - (52 + 48) = 80° (sum of triangle)

b = 130 in.

B = 48°

Plug in the values

\frac{130}{sin(48)} = \frac{x}{sin(80)}

Multiply both sides by sin(80)

\frac{130*sin(80)}{sin(48)} = x

172.274641 = x

x = 172.27 in. (to 2 decimal places)

4 0
2 years ago
Expand.<br> Your answer should be a polynomial in standard form.<br> (3c + 2)(c^2-6c-4)
evablogger [386]

Answer:

After expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

Step-by-step explanation:

We need to expand the polynomial (3c + 2)(c^2-6c-4)

Multiply the terms:

(3c + 2)(c^2-6c-4)\\=3c(c^2-6c-4)+2(c^2-6c-4)\\=3c^3-18c^2-12c+2c^2-12c-8\\=3c^3-18c^2+2c^2-12c-12c-8\\=3c^3-16c^2-24c-8

So, after expanding the polynomial (3c + 2)(c^2-6c-4) we get  3c^3-16c^2-24c-8

3 0
3 years ago
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