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o-na [289]
3 years ago
5

About how many pounds of coffee will you need to make 600 medium cups of coffee?

Mathematics
1 answer:
Veronika [31]3 years ago
6 0

Answer:

A. 10

Step-by-step explanation:

I found a website that explains that you need 8.3 grams of coffee to make one 5-fl oz cup of coffee.

To make 600 cups, you need 600 * 8.3 g = 4980 g

Now we convert 4980 g to lb.

1 lb = 454 g

4980 g * (1 lb)/(454 g) = 11 lb

The closest answer is A. 10

Answer: A. 10

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30000mm how much did it grow in a meter
Serggg [28]
30000mm÷10=3000cm
3000cm÷100=30m
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7 0
3 years ago
The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at
satela [25.4K]
The total cost is the dependant variable and the number of tickets along with flat out price is the independent variable.

The equation would be y = 1.25x + ?

You would insert 25 for x which equals 31.25 and insert 43.75 for y.

43.75 = 31.25 + ? Then subtract 31.25 from both sides of the equation and you would get....

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That is your flat rate to get in to the fair 




7 0
4 years ago
Q - 0.63 = 1.16<br> solve for q. please
devlian [24]

Answer: Q=1.79

Step-by-step explanation: Move 0.63 to the right and add both numbers then calculate it. So Q=1.79

7 0
3 years ago
A group of hikers walked 2 1/4 km in 3/4 hour.The distance here varies directly with time. What is the constant of variation?
telo118 [61]

The distance depends on the time.

So now we need to find the constant of variation or the constant of proportionality.

To do so we must find y(the dependent variable) and x(the independent variable).

To find the constant(k) we must find y/x

Since y/x=k

Then 2.25/.75=k

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3 0
3 years ago
Read 2 more answers
Find the Antilog of 547.840​
bija089 [108]

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

{ \boxed{ \bf{antilog \: of \: x =  \frac{x}{ log} =  {10}^{x}  }}}

Therefore:

{ \sf{anti(547.840) =  {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}

3 0
3 years ago
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