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34kurt
3 years ago
8

Find the product. Tell which strategy you need. 9 x 199

Mathematics
2 answers:
arsen [322]3 years ago
5 0
The product is another word for multiplying so 9* 199 is 1791
kherson [118]3 years ago
4 0
All you need to do is multiply it so it will be 1,791
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The fish tank has side lengths 20in, 10in and height 15in. The water level is two inches below the top of the tank. A glass sphe
Kitty [74]

Answer:

Part 1) The new distance from the water to the top of the tank is 1.979\ in

Part 2) The maximum number of balls that can be put into the tank with the tank not overflowing is 95

Step-by-step explanation:

step 1

Find the total volume of the tank

V=20*10*15=3,000\ in^{3}

step 2

Find the volume of the tank if the water level is two inches below the top of the tank

V=20*10*(15-2)=2,600\ in^{3}

step 3

Find the volume of the glass sphere

The volume of the glass sphere is equal to

V=\frac{4}{3}\pi r^{3}

we have

r=1\ in

assume

\pi=3.14

substitute

V=\frac{4}{3}(3.14)(1)^{3}

V=4.2\ in^{3}

step 4

What is the new distance from the water to the top of the tank?

we know that

2 in -----> represent (3,000-2,600)=400\ in^{3}

so

using proportion

Find how many inches correspond a volume of 4.2\ in^{3}

\frac{2}{400}\frac{in}{in^{3}}=\frac{x}{4.2}\frac{in}{in^{3}}\\ \\x=4.2*2/400\\ \\x=0.021\ in

The new distance from the water to the top of the tank is

2-0.021=1.979\ in

step 5

Find how many of these balls can be put into the tank with the tank not overflowing

we know that

The volume of one ball is equal to  4.2\ in^{3}

using proportion

\frac{1}{4.2}=\frac{x}{400}\\ \\x=400/4.2\\ \\x=95.23\ balls

therefore

The maximum number of balls that can be put into the tank with the tank not overflowing is 95

4 0
3 years ago
There are 64 pretzels in a 16 ounce bag of chocolate covered pretzels.
FromTheMoon [43]
16:64
5:x (Cross Multiply)
16x = 64*5
16x = 320 (Then Divide both sides by 16 to isolate x)
x= 20
5 0
3 years ago
Tickets to a local circus cost $5 for students and $8 for adults. A group of 9 people spent a total of $60. How many adults were
S_A_V [24]

Answer:

5

Step-by-step explanation:

You need to set up and solve a system of linear equations here.

Let s and a represent the number of students and adults respectively.

Then s + a = 9, and s = 9 - a.

Total ticket cost for the adults was ($8/adult)(a)

and for the students ($5/student)(s).

Total cost of the tickets was then  ($8/adult)(a) + ($5/student)(s) = $60.

Then our system of linear equations is:

8a + 5s = 60

 a  +  s  = 9, or s = 9 - a.  Substituting 9 - a for s, we get:

8a + 5(9 - a) = 60.

Then 8a + 45 - 5a = 60, or 3a = 15.

Solving for a, we get a = 5.

Solving for s using s = 9 - a, we get   s = 9 - 5, or s = 4.

There were 5 adults in the group (and 4 students).

3 0
3 years ago
How would I do the steps to solve this?
allsm [11]

Answer:

The maximum revenue is 16000 dollars (at p = 40)

Step-by-step explanation:

One way to find the maximum value is derivatives. The first derivative is used to find where the slope of function will be zero.

Given function is:

R(p) = -10p^2+800p

Taking derivative wrt p

\frac{d}{dp} (R(p) = \frac{d}{dp} (-10p^2+800p)\\R'(p) = -10 \frac{d}{dp} (p^2) +800 \ frac{d}{dp}(p)\\R'(p) = -10 (2p) +800(1)\\R'(p) = -20p+800\\

Now putting R'(p) = 0

-20p+800 = 0\\-20p = -800\\\frac{-20p}{-20} = \frac{-800}{-20}\\p = 40

As p is is positive and the second derivative is -20, the function will have maximum value at p = 40

Putting p=40 in function

R(40) = -10(40)^2 +800(40)\\= -10(1600) + 32000\\=-16000+32000\\=16000

The maximum revenue is 16000 dollars (at p = 40)

3 0
2 years ago
Please help i will give 5 stars
NeTakaya
1. C = 10π; A = 25π
2. 254.34
3. 12
4. without a picture it is just a shot 390 mm3
5. 12
8 0
3 years ago
Read 2 more answers
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