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RSB [31]
3 years ago
10

What is the real answer !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

?
Mathematics
1 answer:
Troyanec [42]3 years ago
3 0
Real answer for what??
You might be interested in
Solve this system of equations. y = 5x +20 and y = -2x -8
Thepotemich [5.8K]

Answer:

y = 0

x = -4

( x, y ) = ( -4 , 0 )

Step-by-step explanation:

y = 5x + 20

y = -2x - 8

Substitute

5x + 20 = -2x - 8

Add 8 on both sides

5x + 20 + 8 = -2x - 8 + 8

5x + 28 = -2x

Subtract 5x on both sides

5x - 5x + 28 = -2x - 5x

28 = -7x

Divide by -7 on both sides

28/-7 = -7x/-7

-4 = x

Now that you have x, you can substitute it in one of the equations that was given to find the value of y.

y = 5x + 20

y = 5(-4) + 20

y = -20 + 20

y = 0

Or....

y = -2x - 8

y = -2(-4) - 8

y = 8 - 8

y = 0

They will both be 0 no matter what

Point form = ( -4, 0 )

Hope this helped

3 0
3 years ago
Solve 2m + 4m - 3m squared
Vitek1552 [10]

Answer:

3m^2

Step-by-step explanation:

i hope this helps!! :)

4 0
3 years ago
What is the remainder of x^5+2x^4+9x^3-6x^2+3x+3165 divided by x-5
riadik2000 [5.3K]

Answer:

8530

Step-by-step explanation:

The remainder is 5⁵ + 2(5)⁴ + 9(5)³ - 6(5)² + 3(5) + 3165 = 8530

4 0
2 years ago
Is 9/27 squared rational?
aniked [119]
Yes because it can be expressed as a fraction (9/27)
4 0
3 years ago
Read 2 more answers
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter
Goshia [24]

Answer:

The question is incomplete, this is the complete question.;

There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.

The answer to the question is;

the probability of this occurring is 1/27

Step-by-step explanation:

Let n(N) =5 ( the number of nickels)

n(D) =5 ( the number of dimes) and

n(Q) = 5 ( the number of quarters)

P(N)= 5/15=1/3 (prob of picking a nickel)

P(D) =5/15=1/3 (prob of picking a dime)

P(Q) = 5/15= 1/3 (prob of picking a quatre)

The probability of picking the three= P(N)×P(D)×P(Q)

= 1/3×1/3×1/3

= 1/27

7 0
3 years ago
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