$f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\$

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Work shown for part 2

$(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\$

6 0

2 years ago

Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are 6 questions, e

Kisachek [45]

Answer:

P=20%

Step-by-step explanation:

Let's suppose that each question in the test has one and only one correct answer. This means we have 1 desired outcome out of the total 5 desired outcomes. Therefore:

Probability=#of desired outcomes / #of possible outcomes

$P=\frac{1 correct}{5 opctions}$

$P=\frac{1}{5}$

P=0.20

P=20%

7 0

3 years ago