<u>Given </u><u>:</u><u>-</u><u> </u>
- Mrs. Smith left a 15% tip for a dinner that cost $62.40.
<u>To </u><u>find</u><u> </u><u>:</u><u>-</u><u> </u>
- About how much tip did Mrs. Smith leave?
<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>
The tip is 15% of $62.40 .
<u>•</u><u> </u><u>Calculating</u><u> </u><u>1</u><u>5</u><u>%</u><u> </u><u>of </u><u>$</u><u>6</u><u>2</u><u>.</u><u>4</u><u>0</u><u> </u>
- $ 62.40 * 15%
- $ 62.40 * 15/100
- $ 9.36
Answer:
Correct choice is B
Step-by-step explanation:
In step 4 were proved that 
By definition, similar triangles have proportional lengths of corresponding sides. To the side AB corresponds side ED, to the side AC corresponds side DC and to the side BC corresponds side EC. Thus,
He would be 25 inches tall.
40 divided by 8 would equal 5 so at age 1, he was 5 inches tall. So 5 times 5 which is how old he was, would equal 25 inches.
1+1 is equal to 3-1. 1+1=2. 3-1=2. 2=2
Answer:
Step-by-step explanation:
The diagram of the triangles are shown in the attached photo.
1) Looking at ∆AOL, to determine AL, we would apply the sine rule
a/SinA = b/SinB = c/SinC
21/Sin25 = AL/Sin 105
21Sin105 = ALSin25
21 × 0.9659 = 0.4226AL
AL = 20.2839/0.4226
AL = 50
Looking at ∆KAL,
AL/Sin55 = KL/Sin100
50/0.8192 = KL/0.9848
50 × 0.9848 = KL × 0.8192
KL = 49.24/0.8192
KL = 60
AK/Sin25 = AL/Sin 55
AKSin55 = ALSin25
AK × 0.8192 = 0.4226 × 50
AK = 21.13/0.8192
AK = 25.8
2) looking at ∆AOC,
Sin 18 = AD/AC = 18/AC
AC = 18/Sin18 = 18/0.3090
AC = 58.25
Sin 85 = AD/AB = 18/AB
AB = 18/Sin85 = 18/0.9962
AB = 18.1
To determine BC, we would apply Sine rule.
BC/Sin77 = 58.25/Sin85
BCSin85 = 58.25Sin77
BC = 58.25Sin77/Sin85
BC = 58.25 × 0.9744/0.9962
BC = 56.98
