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Neporo4naja [7]
3 years ago
15

The sum of the measures of the angles of a triangle is 180. The sum of the measures of the second and third angles is five times

the measure of the first angle. The third angle is 10 more than the second. Let x, y, and z represent the measures of the first, second, and third angles, respectively. Find the measures of the three angles
Mathematics
1 answer:
erastova [34]3 years ago
8 0

Answer:

1st ∡ = 15.5°

2nd ∡ = 77.25°

3rd ∡ = 87.25°

Step-by-step explanation:

1st ∡:  x

2nd ∡:  y

3rd ∡:  z

Equations we can create from data given in problem:

y + z = 5x

z = 5x + 10

We have enough expressions to create an equation:

x + 5x + 5x + 10 = 180

11x = 170

x = 15.5

y = 5(15.5) = 77.25

z = y + 10 = 87.25

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Step-by-step explanation:

30/2 = 15ft/s

55/4 = 13.75ft/s

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The product of 25 and an unknown number is subtracted from 36. The result is -114.
svetlana [45]
Let x = the unknown number to get x = 6

3 0
3 years ago
A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021
egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

  • A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

  • \displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

  • \displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}

Therefore, for the last term we have;

  • \displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

\displaystyle \frac{A}{2}  = \mathbf{ 1011 \cdot  \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460}  \right)}

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2} +\frac{1}{2} -  \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022}  \right)

Which gives;

\displaystyle \frac{A}{2}  = 1011 \cdot  \left(1 - \frac{1}{2022}  \right)

\displaystyle  A = 2 \times 1011 \cdot  \left(1 - \frac{1}{2022}  \right) = \frac{1032231}{511} \approx \mathbf{2020.022}

  • A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0
2 years ago
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Answer:

15

Step-by-step explanation:

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5 0
2 years ago
What is 520 x 2<br> a 1040<br> b 1140<br> c 1340
MissTica
Your answer would be A 1040.
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