Given:
You know that:
In order to solve the operation, you can follow these steps:
1. Distribute the negative signs. Remember the Sign Rules for Multiplication:
Then:
2. Combine the like terms (add the Real Parts and add the Imaginary Parts):
Hence, the answer is: Option B.
Answer:
D
Step-by-step explanation:
Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).
Consider option A.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = 1 has the rule (x,2-y). So,
These points are exactly the vertices of the initial square.
Consider option B.
1st transformation will map vertices of the square into points
2nd transformation = reflection over x = 3 has the rule (6-x,y). So,
These points are exactly the vertices of the initial square.
Consider option C.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 7 will map vertices into points
These points are exactly the vertices of the initial square.
Consider option D.
1st transformation will map vertices of the square into points
2nd transformation = reflection over y = -x + 2 will map vertices into points
These points are not the vertices of the initial square.
Answer:
-2n²
Step-by-step explanation:
Using the image attached:
We see that the second differences (blue ones) are all equal so we conclude that this is a quadratic sequence.
The quadratic sequence has the form:
To find the value of a we just divide second difference ( -4 ) by 2:
Now we have:
Substitute and
into the equation above:
Since = -2 and
= -8 , after simplification we have:
The solution of this system is:
The general term is :
