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3 years ago

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i am even number smaller than 48 but not greater than 30 i am multiple of 6 and factor of 72 what number i am

1 answer:

tigry1 [53]3 years ago

7 0

Answer:

36

Step-by-step explanation:

<u>Even number smaller than 48 but not greater than 30 i am multiple of 6:</u>

30, 36, 42

<u>Factor of 72:</u>

2, 3, 6, 8, 9, 12, 24, 36, 72

So the number is 36

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Nikitich [7]

10 x 10 x 10 = $10^{3}$

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3 years ago

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A robot can complete up to 8 tasks in 5/6 hour. each task takes the same amount of time.

storchak [24]

$\bf \begin{array}{ccll} tasks&hours\\ \cline{1-2}&\\ 8&\frac{5}{6}\\\\ 1&h \end{array}\implies \cfrac{8}{1}=\cfrac{~~\frac{5}{6}~~}{h}\implies 8=\cfrac{~~\frac{5}{6}~~}{\frac{h}{1}}\implies 8=\cfrac{5}{6}\cdot \cfrac{1}{h} \\\\\\ 8=\cfrac{5}{6h}\implies 48h=5\implies h=\cfrac{5}{48}\\\\[-0.35em] \rule{31em}{0.25pt}$

$\bf \begin{array}{ccll} tasks&hours\\ \cline{1-2}&\\ 8&\frac{5}{6}\\\\ t&1 \end{array}\implies \cfrac{8}{t}=\cfrac{~~\frac{5}{6}~~}{1}\implies \cfrac{8}{t}=\cfrac{5}{6}\implies 48=5t \\\\\\ \cfrac{48}{5}=t\implies 9\frac{3}{5}=t$

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3 years ago

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Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

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4 years ago

1/8 in the form of 2^N

KIM [24]

Answer:

1.0905

Step-by-step explanation:

3 0

3 years ago

Pls help what is this as a simplified fraction (thank u Jesus loves u)

GaryK [48]

Answer:

-500/11

Step-by-step explanation:

0.22 in fraction is 11/50

After replacing the decimal with a fraction, subtract it from -10.

You'll have -10÷(11/50)

You'll then change the division sign to a multiplication sign.

You'll then have that -10 × 50/11

-10×50 = -500/11.

6 0

2 years ago