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sineoko [7]
3 years ago
8

Find the size of angle XYZ.Give your answer to 1 decimal place.Z13 cmxY4 cm​

Mathematics
2 answers:
Rzqust [24]3 years ago
7 0

Answer:

<h2><em>7</em><em>2</em><em>.</em><em>9</em><em>°</em></h2>

<em>sol</em><em>ution</em><em>,</em>

<em>tan \: y \:  =  \frac{13}{4}  \\ y =  {tan}^{ - 1}  ( \frac{13}{4} ) \\ y = 72.9</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

Margarita [4]3 years ago
6 0

Answer:

13.6cm

EXPLANATION:USE Pythagoras Rule

13²+ 4²

169 + 16 = 189

FIND THE SQUARE ROOT OF 185

√185 = 13.6015

TO 1.dp

<h3>13.6cm</h3>

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The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi
Tresset [83]

Answer:

a

  P(X \le 250 ) =  0.7564 [/tex]  ,  P(X <  250 )  =  0.7564   ,

    P(X <  300 )  =  0.09922

b

P(100 <  X  < 250 ) =0.644

c

 x  = 192.1

Step-by-step explanation:

From the question we are told that

   The value for \alpha  =  2.6

    The value for \beta = 220

Generally the  Weibull distribution function is mathematically represented as

      F( x , \alpha ,  \beta ) =  \left \{  0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  x < 0} \atop { 1- e^{-(\frac{x}{\beta } )^{\alpha } }}\ \ \ \ \ \ x \ge 0} \right

Generally the probability that a specimen's lifetime is at most 250 is mathematically represented as

      P(X \le  250 ) =  F(250, 2.7 , 220 )

      P(X \le 250 )=1 - e^{- (\frac{250}{220} )^{2.7}}

      P(X \le 250 ) =  1 - 0.2436

      P(X \le 250 ) =  0.7564

Generally the probability that a specimen's lifetime is less than 250

      P(X <  250 ) =  F(250, 2.7 , 220 )

      [texP(X <  250 ) =1 - e^{- (\frac{250}{220} )^{2.7}}[/tex]

      P(X <  250 )  =  1 - 0.2436

      P(X <  250 )  =  0.7564    

Generally the probability that a specimen's lifetime is more than 300

     P(X >  300 ) = 1- p(X \le 300 )

      P(X >  300 ) = 1-  F(300, 2.7 , 220 )

      [texP(X <  300) =1- [1 - e^{- (\frac{300}{220} )^{2.7}}][/tex]

      P(X <  300 )  =  0.09922

Generally the probability that a specimen's lifetime is between 100 and 250 is

     P(100 <  X  < 250 ) =  P(X < 250) - P(X < 100)

=>  P(100 <  X  < 250 ) =F(250 , 2.7 , 220 ) - F(100 , 2.7 , 220 )

=>  P(100 <  X  < 250 ) =(1 - e^{-(\frac{250}{220})^{2.7}}) - (1 - e^{-(\frac{100}{220})^{2.7}})

=>  P(100 <  X  < 250 ) = (1 - 0.244 ) - (1- 0.888)

=>  P(100 <  X  < 250 ) =0.644

Generally the value  such that exactly 50% of all specimens

    P(X > x) = 1-P(X <  x) = 0.50

=>  P(X > x) = 1- (1 - e^{- (\frac{x}{220}) ^{2.7}}) = 0.50

=>  P(X> x ) = e^(- \frac{x}{20})^{2.7}  = 0.50

=>  P(X> x ) = (- \frac{x}{20})^{2.7}  = ln0.50

=>   P(X> x ) =  \frac{x}{20}  =[ -ln0.50 ] ^{frac{1}{2.7}}

=>   x  = 220[ -ln0.50 ] ^{frac{1}{2.7}}

=>   x  = 192.1

     

8 0
4 years ago
Calculate the slope of the line on the graph
Tamiku [17]

Answer:

3.5 (meters per second)

Step-by-step explanation:

To calculate the slope, we need two points. Let's see if we can select two points from the graph.

From the graph, we can pick out two possible points.

At the beginning, (0,2.5) is a valid candidate.

And at the end, with (5,20). Thus, let's use the slope formula to calculate the slope.

The slope formula is:

m=\frac{y_2-y_1}{x_2-x_1}

Let (0,2.5) be x₁ and y₁ and let (5,20) be x₂ and y₂. Thus:

m=\frac{20-2.5}{5-0}

Simplify:

m=\frac{17.5}{5}\\ m=3.5

Thus, the slope is 3.5 meters per second.

Further notes:

And the entire equation will be:

m=3.5s+2.5

3 0
3 years ago
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