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BARSIC [14]
3 years ago
6

What single transformation was applied to quadrilateral A to get to quadrilateral B

Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer:

b. rotation

Step-by-step explanation:

laiz [17]3 years ago
3 0

Answer:

B. a rotation

Step-by-step explanation:

The shape appears to have the same size, but it has been moved in a way that  is not reflection. Through the process of elimination, the answer is rotation.

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Apply the distributive property<br><br> 1/4(16a+8b+c)
frez [133]

Answer:

4a + 2b + 1/4 c.

Step-by-step explanation:

1/4(16a+8b+c)

= 1/4 * 16a + 1/4 * 8b + 1/4 * c

= 4a + 2b + 1/4 c.

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3 years ago
Rearrange the formula to make a the subject:<br> B = 1/2h(a+b)
Mkey [24]

Answer:

Step-by-step explanation:

B=2h(a+b) #the numerator goes to the other side, the denominator then just makes it B

B/2h=a+b

2h=a+b/B

2h-a=b/B

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318125267

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8 0
2 years ago
Read 2 more answers
Suppose that surface σ is parameterized by r(u,v)=⟨ucos(3v),usin(3v),v⟩, 0≤u≤7 and 0≤v≤2π3 and f(x,y,z)=x2+y2+z2. Set up the sur
Bad White [126]

Looks like you have most of the details already, but you're missing one crucial piece.

\sigma is parameterized by

\vec r(u,v)=\langle u\cos3v,u\sin3v,v\rangle

for 0\le u\le7 and 0\le v\le\frac{2\pi}3, and a normal vector to this surface is

\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\left\langle\sin3v,-\cos3v,3u\right\rangle

with norm

\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{\sin^23v+(-\cos3v)^2+(3u)^2}=\sqrt{9u^2+1}

So the integral of f(x,y,z)=x^2+y^2+z^2 is

\displaystyle\iint_\sigma f(x,y,z)\,\mathrm dA=\boxed{\int_0^{2\pi/3}\int_0^7(u^2+v^2)\sqrt{9u^2+1}\,\mathrm du\,\mathrm dv}

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3 years ago
What is 4.8 as a mixed number
Alex Ar [27]
4 and 8/10 but simplified it's 4 and 2/5
6 0
3 years ago
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